我一直将电话号码存储为long类型，现在我想在将电话号码作为字符串打印时添加连字符。
我尝试使用DecimalFormat，但是它不支持连字符。可能是因为它是用于格式化十进制数而不是长整数。
long phoneFmt = 123456789L;
DecimalFormat phoneFmt = new DecimalFormat("###-###-####");
System.out.println(phoneFmt.format(phoneNum)); //doesn't work as I had hoped
new DecimalFormat("(###)-###-####");
你可以使用String.replaceFirst方法并使用正则表达式的方式进行替换，例如：
long phoneNum = 123456789L;
System.out.println(String.valueOf(phoneNum).replaceFirst("(\\d{3})(\\d{3})(\\d+)", "($1)-$2-$3"));
long phoneFmt = 123456789L;
//get a 12 digits String, filling with left '0' (on the prefix)
DecimalFormat phoneDecimalFmt = new DecimalFormat("0000000000");
String phoneRawString= phoneDecimalFmt.format(phoneFmt);
java.text.MessageFormat phoneMsgFmt=new java.text.MessageFormat("({0})-{1}-{2}");
//suposing a grouping of 3-3-4
String[] phoneNumArr={phoneRawString.substring(0, 3),
phoneRawString.substring(3,6),
phoneRawString.substring(6)};
System.out.println(phoneMsgFmt.format(phoneNumArr));
控制台上的结果如下：
(012)-345-6789
如果要存储电话号码，则应该考虑使用数据类型而不是数字。
最简单的方法是使用javax.swing.text库中内置的MaskFormatter。
您可以像这样操作：
import javax.swing.text.MaskFormatter;
String phoneMask= "###-###-####";
String phoneNumber= "123423452345";
MaskFormatter maskFormatter= new MaskFormatter(phoneMask);
maskFormatter.setValueContainsLiteralCharacters(false);
maskFormatter.valueToString(phoneNumber) ;
如果你真的需要正确的方法，那么你可以使用谷歌最近开源的libphonenumber。
import com.google.i18n.phonenumbers.NumberParseException;
import com.google.i18n.phonenumbers.PhoneNumberUtil;
import com.google.i18n.phonenumbers.Phonenumber;
String s = "18005551234";
PhoneNumberUtil phoneUtil = PhoneNumberUtil.getInstance();
Phonenumber.PhoneNumber phoneNumber = phoneUtil.parse(s, Locale.US.getCountry());
String formatted = phoneUtil.format(phoneNumber, PhoneNumberUtil.PhoneNumberFormat.NATIONAL);
在此处，您可以将库添加到类路径中：http://mvnrepository.com/artifact/com.googlecode.libphonenumber/libphonenumber
StringBuilder sb = new StringBuilder();
long tmp = phoneFmt;
sb.append("(");
sb.append(tmp / 10000000);
tmp = tmp % 10000000;
sb.append(")-");
sb.apppend(tmp / 10000);
tmp = tmp % 10000000;
sb.append("-");
sb.append(tmp);
private String printPhone(Long phoneNum) {
StringBuilder sb = new StringBuilder(15);
StringBuilder temp = new StringBuilder(phoneNum.toString());
while (temp.length() < 10)
temp.insert(0, "0");
char[] chars = temp.toString().toCharArray();
sb.append("(");
for (int i = 0; i < chars.length; i++) {
if (i == 3)
sb.append(") ");
else if (i == 6)
sb.append("-");
sb.append(chars[i]);
}
return sb.toString();
}
DecimalFormat 和 MessageFormat。使用此方法，你几乎可以使用任何东西（String,Integer,Float,Double），输出始终是正确的。import java.text.DecimalFormat;
import java.text.MessageFormat;
/**
* Created by Yamil Garcia Hernandez on 25/4/16.
*/
public class test {
// Constants
public static final DecimalFormat phoneFormatD = new DecimalFormat("0000000000");
public static final MessageFormat phoneFormatM = new MessageFormat("({0}) {1}-{2}");
// Example Method on a Main Class
public static void main(String... args) {
try {
System.out.println(formatPhoneNumber("8091231234"));
} catch (Exception e) {
e.printStackTrace();
}
try {
System.out.println(formatPhoneNumber("18091231234"));
} catch (Exception e) {
e.printStackTrace();
}
try {
System.out.println(formatPhoneNumber("451231234"));
} catch (Exception e) {
e.printStackTrace();
}
try {
System.out.println(formatPhoneNumber("11231234"));
} catch (Exception e) {
e.printStackTrace();
}
try {
System.out.println(formatPhoneNumber("1231234"));
} catch (Exception e) {
e.printStackTrace();
}
try {
System.out.println(formatPhoneNumber("231234"));
} catch (Exception e) {
e.printStackTrace();
}
try {
System.out.println(formatPhoneNumber(""));
} catch (Exception e) {
e.printStackTrace();
}
try {
System.out.println(formatPhoneNumber(0));
} catch (Exception e) {
e.printStackTrace();
}
try {
System.out.println(formatPhoneNumber(8091231234f));
} catch (Exception e) {
e.printStackTrace();
}
}
// Magic
public static String formatPhoneNumber(Object phone) throws Exception {
double p = 0;
if (phone instanceof String)
p = Double.valueOf((String) phone);
if (phone instanceof Integer)
p = (Integer) phone;
if (phone instanceof Float)
p = (Float) phone;
if (phone instanceof Double)
p = (Double) phone;
if (p == 0 || String.valueOf(p) == "" || String.valueOf(p).length() < 7)
throw new Exception("Paramenter is no valid");
String fot = phoneFormatD.format(p);
String extra = fot.length() > 10 ? fot.substring(0, fot.length() - 10) : "";
fot = fot.length() > 10 ? fot.substring(fot.length() - 10, fot.length()) : fot;
String[] arr = {
(fot.charAt(0) != '0') ? fot.substring(0, 3) : (fot.charAt(1) != '0') ? fot.substring(1, 3) : fot.substring(2, 3),
fot.substring(3, 6),
fot.substring(6)
};
String r = phoneFormatM.format(arr);
r = (r.contains("(0)")) ? r.replace("(0) ", "") : r;
r = (extra != "") ? ("+" + extra + " " + r) : r;
return (r);
}
}
(809) 123-1234
+1 (809) 123-1234
(45) 123-1234
(1) 123-1234
123-1234
023-1234
java.lang.NumberFormatException: empty String
at sun.misc.FloatingDecimal.readJavaFormatString(FloatingDecimal.java:1842)
at sun.misc.FloatingDecimal.parseDouble(FloatingDecimal.java:110)
at java.lang.Double.parseDouble(Double.java:538)
at java.lang.Double.valueOf(Double.java:502)
at test.formatPhoneNumber(test.java:66)
at test.main(test.java:45)
java.lang.Exception: Paramenter is no valid
at test.formatPhoneNumber(test.java:78)
at test.main(test.java:50)
(809) 123-1232
您可以使用我的工具类对任何包含非数字字符的字符串进行格式化，以符合您的要求。
public static void main(String[] args){
String num = "ab12345*&67890";
System.out.println(PhoneNumberUtil.formateToPhoneNumber(num,"(XXX)-XXX-XXXX",10));
}
您可以指定任何格式，例如 XXX-XXX-XXXX 和电话号码的长度。如果输入长度大于指定的长度，则字符串将被修剪。
从这里获取我的类：https://github.com/gajeralalji/PhoneNumberUtil/blob/master/PhoneNumberUtil.java
Pattern phoneNumber = Pattern.compile("(\\d{3})(\\d{3})(\\d{4})");
// ...
Matcher matcher = phoneNumber(numberAsLineOf10Symbols);
if (matcher.matches) {
return "(" + matcher.group(1) + ")-" +matcher.group(2) + "-" + matcher.group(3);
}
long）存储并不是一个好主意。电话号码实际上是一种标识，而不是你想进行计算的数字。如果一个电话号码以0开头，那么你无法将其存储在数字类型中。 - Jesper