假设我需要管理一个由任意文件夹/文件结构组成的Zip存档物。在Maven中如何以最符合“Maven方式”的方式完成这项任务不是很清楚。我知道没有“zip”打包类型。这是否意味着在Maven中没有通用的生命周期来简单地将资源文件夹中的内容压缩并安装/部署到我的存储库中?我正在寻找选项,并评估每个选项如何满足我遵循Maven方式的要求。因为我不想承担违背黄金路径的明显惩罚。
决定你将使用哪种分类器来处理你的zip
文件,为了举例,我们假设它将是sample
。
在你的项目中创建文件assembly/sample.xml
填写assembly/sample.xml
,类似于这样:
<?xml version="1.0" encoding="UTF-8"?>
<assembly
xmlns="http://maven.apache.org/plugins/maven-assembly-plugin/assembly/1.1.2"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="
http://maven.apache.org/plugins/maven-assembly-plugin/assembly/1.1.2
http://maven.apache.org/xsd/assembly-1.1.2.xsd"
>
<id>sample</id>
<formats>
<format>zip</format>
</formats>
<fileSets>
<fileSet>
<outputDirectory>/</outputDirectory>
<directory>some/directory/in/your/project</directory>
</fileSet>
</fileSets>
<!-- use this section if you want to package dependencies -->
<dependencySets>
<dependencySet>
<outputDirectory>lib</outputDirectory>
<excludes>
<exclude>*:pom</exclude>
</excludes>
<useStrictFiltering>true</useStrictFiltering>
<useProjectArtifact>false</useProjectArtifact>
<scope>runtime</scope>
</dependencySet>
</dependencySets>
</assembly>
将以下内容添加到您的 build
部分中的 pom 文件:
<build>
<plugins>
<plugin>
<groupId>org.apache.maven.plugins</groupId>
<artifactId>maven-assembly-plugin</artifactId>
<executions>
<execution>
<id>create-distribution</id>
<phase>package</phase>
<goals>
<goal>single</goal>
</goals>
<configuration>
<descriptors>
<descriptor>assembly/sample.xml</descriptor>
</descriptors>
</configuration>
</execution>
</executions>
</plugin>
</plugins>
</build>
作为结果,它应该创建并安装you-project-name-VERSION-sample.zip
。在assembly/sample.xml中填写类似于以下内容:
<assembly xmlns="http://maven.apache.org/plugins/maven-assembly-plugin/assembly/1.1.0" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://maven.apache.org/plugins/maven-assembly-plugin/assembly/1.1.0 http://maven.apache.org/xsd/assembly-1.1.0.xsd">
<id>install</id>
<baseDirectory>/</baseDirectory>
<formats>
<format>zip</format>
</formats>
<fileSets>
<fileSet>
<includes>
<include>README*</include>
<include>*.sh</include>
</includes>
</fileSet>
<fileSet>
<directory>target/classes/</directory>
<outputDirectory>resources</outputDirectory>
<includes>
<include>*.properties</include>
<include>*.xml</include>
</includes>
<lineEnding>dos</lineEnding>
</fileSet>
<!--
<fileSet>
<directory>target/</directory>
<outputDirectory>lib</outputDirectory>
<includes>
<include>*.jar</include>
</includes>
<lineEnding>dos</lineEnding>
</fileSet>
-->
</fileSets>
<!-- use this section if you want to package dependencies -->
<dependencySets>
<dependencySet>
<outputDirectory>lib</outputDirectory>
<excludes>
<exclude>*:pom</exclude>
</excludes>
<useStrictFiltering>true</useStrictFiltering>
<useProjectArtifact>true</useProjectArtifact>
<scope>runtime</scope>
</dependencySet>
</dependencySets>
</assembly>
请在pom.xml文件中添加以下代码。
<plugin>
<groupId>org.apache.maven.plugins</groupId>
<artifactId>maven-assembly-plugin</artifactId>
<configuration>
<descriptor>assembly/sample.xml</descriptor>
</configuration>
<executions>
<execution>
<phase>package</phase>
<goals>
<goal>single</goal>
</goals>
</execution>
</executions>
</plugin>
运行以下命令:mvn package -P dev -Dmaven.test.skip
这将创建包含以下内容的zip文件: xxxx.zip -lib/.jar -resources/.xml/properties -readme -start.sh
<assembly
xmlns="http://maven.apache.org/plugins/maven-assembly-plugin/assembly/1.1.0"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://maven.apache.org/plugins/maven-assembly-plugin/assembly/1.1.0 http://maven.apache.org/xsd/assembly-1.1.0.xsd">
<id>zip</id>
<formats>
<format>zip</format>
</formats>
<includeBaseDirectory>false</includeBaseDirectory>
<fileSets>
<fileSet>
<directory>directoryName of your project</directory>
<outputDirectory>/</outputDirectory>
</fileSet>
</fileSets>
classifier
来完成:https://dev59.com/IILba4cB1Zd3GeqPZhaP - Adam