使用Alamofire发送带有简单字符串的POST请求

Question

使用Alamofire发送带有简单字符串的POST请求

100

如何在我的iOS应用程序中使用Alamofire发送带有简单字符串的POST请求？

作为默认设置，Alamofire需要请求参数：

Alamofire.request(.POST, "http://mywebsite.example/post-request", parameters: ["foo": "bar"])

这些参数包含键值对。但我不想在HTTP主体中发送键值字符串。

我的意思是这样的：

Alamofire.request(.POST, "http://mywebsite.example/post-request", body: "myBodyString")

- Karl

12个回答

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- IsPha · Answer 1

我的情况是，我要发布带有"Content-Type":"application/x-www-form-urlencoded"的alamofire内容，我必须更改alamofire post请求的编码方式

从：JSONENCODING.DEFAULT 到：URLEncoding.httpBody

在这里：

let url = ServicesURls.register_token()
    let body = [
        "UserName": "Minus28",
        "grant_type": "password",
        "Password": "1a29fcd1-2adb-4eaa-9abf-b86607f87085",
         "DeviceNumber": "e9c156d2ab5421e5",
          "AppNotificationKey": "test-test-test",
        "RegistrationEmail": email,
        "RegistrationPassword": password,
        "RegistrationType": 2
        ] as [String : Any]


    Alamofire.request(url, method: .post, parameters: body, encoding: URLEncoding.httpBody , headers: setUpHeaders()).log().responseJSON { (response) in

- SwiftDeveloper · Answer 2

Xcode 8.X，Swift 3.X

易于使用；

 let params:NSMutableDictionary? = ["foo": "bar"];
            let ulr =  NSURL(string:"http://mywebsite.com/post-request" as String)
            let request = NSMutableURLRequest(url: ulr! as URL)
            request.httpMethod = "POST"
            request.setValue("application/json", forHTTPHeaderField: "Content-Type")
            let data = try! JSONSerialization.data(withJSONObject: params!, options: JSONSerialization.WritingOptions.prettyPrinted)

            let json = NSString(data: data, encoding: String.Encoding.utf8.rawValue)
            if let json = json {
                print(json)
            }
            request.httpBody = json!.data(using: String.Encoding.utf8.rawValue);


            Alamofire.request(request as! URLRequestConvertible)
                .responseJSON { response in
                    // do whatever you want here
                   print(response.request)  
                   print(response.response) 
                   print(response.data) 
                   print(response.result)

            }