如何将包含任何字符(包括Unicode字符)的字符串转换为十六进制表示形式,然后反转并从十六进制中获取该字符串?
pack()
和unpack()
函数:function hex2str($hex) {
return pack('H*', $hex);
}
function str2hex($str) {
$unpacked = unpack('H*', $str);
return array_shift($unpacked);
}
$txt = 'This is test';
$hex = str2hex($txt);
$str = hex2str($hex);
echo "{$txt} => {$hex} => {$str}\n";
会产生
这是测试 => 546869732069732074657374 => 这是测试
PHP注意:只有变量应该通过引用传递
。 - Pothercaunpack()
的结果传递给array_shift()
的问题。已修复,谢谢。 - undefined<?php
function bin2hex($str) {
$hex = "";
$i = 0;
do {
$hex .= dechex(ord($str{$i}));
$i++;
} while ($i < strlen($str));
return $hex;
}
// Look what happens when ord($str{$i}) is 0...15
// you get a single digit hexadecimal value 0...F
// bin2hex($str) could return something like 4a3,
// decimals(74, 3), whatever the binary value is of those.
function hex2bin($str) {
$bin = "";
$i = 0;
do {
$bin .= chr(hexdec($str{$i}.$str{($i + 1)}));
$i += 2;
} while ($i < strlen($str));
return $bin;
}
// hex2bin("4a3") just broke. Now what?
// Using sprintf() to get it right.
function bin2hex($str) {
$hex = "";
$i = 0;
do {
$hex .= sprintf("%02x", ord($str{$i}));
$i++;
} while ($i < strlen($str));
return $hex;
}
// now using whatever the binary value of decimals(74, 3)
// and this bin2hex() you get a hexadecimal value you can
// then run the hex2bin function on. 4a03 instead of 4a3.
?>