Python UDP客户端超时机制

3

如果服务器套接字生成的随机数小于4,则我的客户端套接字会在接收数据时挂起。我需要设置超时机制,以便客户端套接字检测到“超时”,然后它将继续发送消息。在运行服务器套接字和客户端套接字后,显示以下错误消息:

Traceback (most recent call last):
File "E:\Studying\Python workspace\Client\src\Client.py", line 34, in <module>
data , addr = client.recvfrom(1024)
socket.timeout: timed out

服务器套接字:

import random
from socket import *
serverSocket = socket(AF_INET , SOCK_DGRAM)
serverSocket.bind(('', 15000))

while True:

rand = random.randint(0, 10)
message , address = serverSocket.recvfrom (1024)
message = message.upper()
print("received message: ", message)
print("echo to address: ", address)
print(rand)

if rand < 4:
    continue
print("Sending message: ", message)
serverSocket.sendto(message, address)

客户端套接字

import socket

UDP_IP = "127.0.0.1"
RPORT = 15000
MESSAGE = "ping"

print("UDP target IP: ", UDP_IP)
print("UDP target port: ", RPORT)
print("message going to send: ", MESSAGE)

client = socket.socket(socket.AF_INET, socket.SOCK_DGRAM)

i=1

while True:
  try:

    if(i<11): 
        client.sendto(MESSAGE.encode('utf_8'),(UDP_IP, RPORT))
        print("sending message: ", MESSAGE)
        print(i)
        i=i+1
        client.settimeout(2)

        data , addr = client.recvfrom(1024)
        print("received echo: ", data)
        print("received at: " , addr )

  finally:
    print("closing socket")
    client.close()
2个回答

4

好的,settimeout()会产生异常。尝试这样做:

while True:
  try:
    if(i<11): 
        client.sendto(MESSAGE.encode('utf_8'),(UDP_IP, RPORT))
        print("sending message: ", MESSAGE)
        print(i)
        i=i+1
        client.settimeout(2)

        data , addr = client.recvfrom(1024)
        print("received echo: ", data)
        print("received at: " , addr )

  except socket.timeout:
    print("closing socket")
    client.close()

如果您想了解有关socket.settimeout()的更多信息,请查看此链接:http://docs.python.org/2/library/socket.html#socket.timeout
希望这可以帮助您!

0
except socket.timeout:
  print("closing socket")
  client.close()

如果client.close()不起作用,只需使用pass

except socket.timeout:
  pass

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