根据我的理解,TCP复位(RST)标志设置是每当接收到的数据段不适用于当前连接时设置的,这会导致终止当前的TCP会话。但下面粘贴的Wireshark捕获似乎并不遵循这个理论。基本上发起RESET(frame#466)的端点A自己尝试在同一TCP会话中重新发送TCP帧,并继续响应来自端点B的任何后续新连接请求[SYN],并且这种行为重复了5次,在第6次尝试(frame#486)三向握手才再次成功。
464 04:35.1 50000 > enpc [PSH, ACK] Seq=31894 Ack=7454 Win=5345 Len=105
465 04:35.2 enpc > 50000 [ACK] Seq=7454 Ack=31999 Win=32127 Len=0
466 04:35.2 50000 > enpc [RST] Seq=31999 Win=0 Len=0
467 04:35.4 [TCP Retransmission] 50000 > enpc [PSH, ACK] Seq=31894 Ack=7454 Win=5345 Len=105
468 04:36.1 [TCP Retransmission] 50000 > enpc [PSH, ACK] Seq=31894 Ack=7454 Win=5345 Len=105
469 04:37.5 [TCP Retransmission] 50000 > enpc [PSH, ACK] Seq=31894 Ack=7454 Win=5345 Len=105
470 04:40.3 [TCP Retransmission] 50000 > enpc [PSH, ACK] Seq=31894 Ack=7454 Win=5345 Len=105
471 04:45.9 [TCP Retransmission] 50000 > enpc [PSH, ACK] Seq=31894 Ack=7454 Win=5345 Len=105
472 04:57.1 [TCP Retransmission] 50000 > enpc [PSH, ACK] Seq=31894 Ack=7454 Win=5345 Len=105
473 05:17.1 fg-fps > 50000 [SYN] Seq=0 Win=65535 Len=0 MSS=1460 WS=2 SACK_PERM=1
474 05:17.1 50000 > fg-fps [RST, ACK] Seq=1 Ack=1 Win=0 Len=0
475 05:17.5 fg-fps > 50000 [SYN] Seq=0 Win=65535 Len=0 MSS=1460 WS=2 SACK_PERM=1
476 05:17.5 50000 > fg-fps [RST, ACK] Seq=1 Ack=1 Win=0 Len=0
477 05:18.0 fg-fps > 50000 [SYN] Seq=0 Win=65535 Len=0 MSS=1460 WS=2 SACK_PERM=1
478 05:18.0 50000 > fg-fps [RST, ACK] Seq=1 Ack=1 Win=0 Len=0
479 05:19.5 [TCP Retransmission] 50000 > enpc [PSH, ACK] Seq=31894 Ack=7454 Win=5345 Len=105
480 05:23.2 fg-gip > 50000 [SYN] Seq=0 Win=65535 Len=0 MSS=1460 WS=2 SACK_PERM=1
481 05:23.2 50000 > fg-gip [RST, ACK] Seq=1 Ack=1 Win=0 Len=0
482 05:23.7 fg-gip > 50000 [SYN] Seq=0 Win=65535 Len=0 MSS=1460 WS=2 SACK_PERM=1
483 05:23.7 50000 > fg-gip [RST, ACK] Seq=1 Ack=1 Win=0 Len=0
484 05:24.2 fg-gip > 50000 [SYN] Seq=0 Win=65535 Len=0 MSS=1460 WS=2 SACK_PERM=1
485 05:24.2 50000 > fg-gip [RST, ACK] Seq=1 Ack=1 Win=0 Len=0
486 05:29.7 dyniplookup > 50000 [SYN] Seq=0 Win=65535 Len=0 MSS=1460 WS=2 SACK_PERM=1
487 05:29.7 50000 > dyniplookup [SYN, ACK] Seq=0 Ack=1 Win=5840 Len=0 MSS=1460 SACK_PERM=1 WS=2
488 05:29.7 dyniplookup > 50000 [ACK] Seq=1 Ack=1 Win=65536 Len=0
489 05:29.7 dyniplookup > 50000 [PSH, ACK] Seq=1 Ack=1 Win=65536 Len=105
490 05:29.7 50000 > dyniplookup [ACK] Seq=1 Ack=106 Win=5840 Len=0
491 05:29.7 dyniplookup > 50000 [PSH, ACK] Seq=106 Ack=1 Win=65536 Len=105
我的问题:
为什么端点A在生成RST的情况下仍然保持在连接上重新传输数据包?
该问题涉及IT技术,需要进一步了解具体背景和情境。