请注意,
这个问题与本回答非常相关,因此我也将这个类作为
那里的一个答案。该答案将接收此类的任何更新。
据我所知,没有内置的方法可以实现此功能。但是,您可以创建自己的类。
所以我这样做了:
public class QueryStringBuilder
{
private readonly List<KeyValuePair<string, object>> _keyValuePairs
= new List<KeyValuePair<string, object>>();
public static string BuildQueryString(object queryData, string argSeperator = "&")
{
var encoder = new QueryStringBuilder();
encoder.AddEntry(null, queryData, allowObjects: true);
return encoder.GetUriString(argSeperator);
}
private string GetUriString(string argSeperator)
{
return String.Join(argSeperator,
_keyValuePairs.Select(kvp =>
{
var key = Uri.EscapeDataString(kvp.Key);
var value = Uri.EscapeDataString(kvp.Value.ToString());
return $"{key}={value}";
}));
}
private void AddEntry(string prefix, object instance, bool allowObjects)
{
var dictionary = instance as IDictionary;
var collection = instance as ICollection;
if (dictionary != null)
{
Add(prefix, GetDictionaryAdapter(dictionary));
}
else if (collection != null)
{
Add(prefix, GetArrayAdapter(collection));
}
else if (allowObjects)
{
Add(prefix, GetObjectAdapter(instance));
}
else
{
_keyValuePairs.Add(new KeyValuePair<string, object>(prefix, instance));
}
}
private void Add(string prefix, IEnumerable<Entry> datas)
{
foreach (var item in datas)
{
var newPrefix = String.IsNullOrEmpty(prefix)
? item.Key
: $"{prefix}[{item.Key}]";
AddEntry(newPrefix, item.Value, allowObjects: false);
}
}
private struct Entry
{
public string Key;
public object Value;
}
private IEnumerable<Entry> GetObjectAdapter(object data)
{
var properties = data.GetType().GetProperties();
foreach (var property in properties)
{
yield return new Entry()
{
Key = property.Name,
Value = property.GetValue(data)
};
}
}
private IEnumerable<Entry> GetArrayAdapter(ICollection collection)
{
int i = 0;
foreach (var item in collection)
{
yield return new Entry()
{
Key = i.ToString(),
Value = item,
};
i++;
}
}
private IEnumerable<Entry> GetDictionaryAdapter(IDictionary collection)
{
foreach (DictionaryEntry item in collection)
{
yield return new Entry()
{
Key = item.Key.ToString(),
Value = item.Value,
};
}
}
}
像这样:
QueryStringBuilder.BuildQueryString(new
{
Age = 19,
Name = "John&Doe",
Values = new object[]
{
1,
2,
new Dictionary<string, string>()
{
{ "key1", "value1" },
{ "key2", "value2" },
}
},
});
QueryStringBuilder.BuildQueryString(new object[]
{
1,
2,
new object[] { "one", "two", "three" },
new Dictionary<string, string>()
{
{ "key1", "value1" },
{ "key2", "value2" },
}
}
);