我正在使用activator上发布的Spring Akka示例来创建Spring管理的bean actors。这是我目前使用的代码,包括演示类:
@Component
class Test extends UntypedActor {
@Autowired
protected ObjectMapper objectMapper;
protected final Account account;
protected final Order order;
public Test(Account account, Order order) {
this.account = account;
this.order = order;
}
@Override
public void onReceive(Object message) throws Exception {
if (message instanceof SomeCommand) {
// Do something using the order and the account;
} else if (message instanceof FooCommand) {
// More stuff
}
}
}
@Component
public class SpringExtension extends AbstractExtensionId<SpringExtensionImpl> implements ExtensionIdProvider {
@Autowired
private ApplicationContext applicationContext;
@Override
public SpringExtensionImpl createExtension(ExtendedActorSystem system) {
return applicationContext.getBean(SpringExtensionImpl.class);
}
@Override
public ExtensionId<? extends Extension> lookup() {
return applicationContext.getBean(SpringExtension.class);
}
}
@Component
public class SpringExtensionImpl implements Extension {
@Autowired
private ApplicationContext applicationContext;
public Props props(String actorBeanName) {
return Props.create(SpringActorProducer.class, applicationContext, actorBeanName);
}
}
public class SpringActorProducer implements IndirectActorProducer {
private final ApplicationContext applicationContext;
private final String actorBeanName;
public SpringActorProducer(ApplicationContext applicationContext, String actorBeanName) {
this.applicationContext = applicationContext;
this.actorBeanName = actorBeanName;
}
@Override
public Actor produce() {
return (Actor) applicationContext.getBean(actorBeanName);
}
@Override
public Class<? extends Actor> actorClass() {
return (Class<? extends Actor>) applicationContext.getType(actorBeanName);
}
}
现在我的问题是,如何使用自定义构造函数参数实例化演员。我考虑过使用工厂或setter方法,但我认为这不是一个选项,因为底层的Actor类不可访问。非常感谢您对此事的任何意见。如果有什么不清楚的地方,请发表评论。
附注:如果您认为我的代码中存在错误或有更好的处理方式,请告诉我!我对Spring和Akka的结合经验很少,所以任何建议都会受到赞赏。