很久以前我就不再写JavaScript代码了,现在有些生疏了。我需要将这样的数组进行拆分:
Object ( [0] => 2013-04-12 [1] => text [2] => text [3] => text [4] => text [5] => 2013-04-11 [6] => text [7] => text [8] => text [9] => text [10] => text [11] => text [12] => 2013-04-10 [13] => text [14] => text [15] => text [16] => text [17] => 2013-04-09 [18] => text [19] => text [20] => text )
转换为JSON对象或数组,其中索引0始终是日期:
Object0 ( [0] => 2013-04-12 [1] => text [2] => text [3] => text [4] => text ) Object1 ( [0] => 2013-04-11 [1] => text [2] => text [3] => text [4] => text [5] => text [6] => text )
Object2 ( [0] => 2013-04-10 [1] => text [2] => text [3] => text [4] => text )
Object3 ( [0] => 2013-04-09 [1] => text [2] => text [3] => text )
因此,我只能使用值来确定每个新数组,这些数组的大小可能不同。感谢您的帮助。
更新:抱歉我没有在最初的问题中发布我的代码,因为我写得太烂了(而且我非常羞愧)。下面是我最终使用的代码,感谢Bangerang的解决方案。感谢大家的帮助和贡献。
Object ( [0] => 2013-04-12 [1] => text [2] => text [3] => text [4] => text [5] => 2013-04-11 [6] => text [7] => text [8] => text [9] => text [10] => text [11] => text [12] => 2013-04-10 [13] => text [14] => text [15] => text [16] => text [17] => 2013-04-09 [18] => text [19] => text [20] => text )
转换为JSON对象或数组,其中索引0始终是日期:
Object0 ( [0] => 2013-04-12 [1] => text [2] => text [3] => text [4] => text ) Object1 ( [0] => 2013-04-11 [1] => text [2] => text [3] => text [4] => text [5] => text [6] => text )
Object2 ( [0] => 2013-04-10 [1] => text [2] => text [3] => text [4] => text )
Object3 ( [0] => 2013-04-09 [1] => text [2] => text [3] => text )
因此,我只能使用值来确定每个新数组,这些数组的大小可能不同。感谢您的帮助。
更新:抱歉我没有在最初的问题中发布我的代码,因为我写得太烂了(而且我非常羞愧)。下面是我最终使用的代码,感谢Bangerang的解决方案。感谢大家的帮助和贡献。
var events = [];
var result = [];
var j = 0;
for (var i = 0; i < tableData.length; i++){
if (/^(\d{4})-(\d{2})-(\d{2})$/.test(tableData[i])){ //Returning true if it's just numbers
j = j + 1;
events[j] = [];
events[j].push(tableData[i]);
result.push(events[j]);
} else {
events[j].push(tableData[i]);
}
}
// Then I write the json message which will be eval to use with FullCalendar.
var json_events = '[';
for (var i = 1; i <= events.length; i++){
if (typeof events[i] !== 'undefined' && events[i].length > 0) {
for (var j = 0; j < events[i].length; j++){
if(/@/.test(events[i][j])){
json_events += '{"start":"' + events[i][0] + '",';
json_events += '"textColor":"black",';
var tmp = events[i][j].split("@");
json_events += '"backgroundColor":"' + tmp[0] + '",';
var text_pattern = new RegExp(/<b>([a-z_]+)<\/b>(.+)/);
var title_desc = text_pattern.exec(tmp[1]);
json_events += '"title":"' + title_desc[1] + '",';
json_events += '"description":"' + title_desc[0] + '"';
json_events += '},';
}
}
}
}
json_events += ']';
json_events = json_events.replace("},]","}]");
/^(\d{4})-(\d{2})-(\d{2})$/
在你的示例中不匹配日期格式。日期是以字符串还是数字存储的? - Kijewskireduce
代替:基于值的数组分割。 - Sebastian Simon