我对realloc的工作原理感到困惑。如果我使用malloc分配了一块缓冲区,并将数据复制到该缓冲区,比如说"AB":
+------------+
| A | B | \0 |
+------------+
我使用realloc重新分配了缓冲区,是否会导致数据丢失(即使只有一个字节)?或者它只是扩展了缓冲区?
+------------------------+
| A | B | \0 | ? | ? | ? |
+------------------------+
代码:
#include<stdio.h>
#include<stdlib.h>
#include<string.h>
int main(void){
char* buffer = (char*) malloc( sizeof(char) * 3 );
strncpy(buffer, "AB", 2);
buffer = (char*) realloc(buffer, sizeof(char) * 6); /* Will there be any lost here? */
free(buffer);
return(0);
}
buffer = realloc(buffer, newsize);
? - ylun.ca