如果您要应用 PIVOT
函数,您需要使用聚合函数来获得结果,但您还希望使用窗口函数如 row_number()
为帐户中的每个联系人生成唯一的序列。
首先,您需要查询类似于:
select account, contact,
'contact'
+ cast(row_number() over(partition by account
order by contact) as varchar(10)) seq
from yourtable
请查看带演示的SQL Fiddle。这将创建一个新列,其中包含唯一的序列:
| ACCOUNT | CONTACT | SEQ |
|
| 1 | 324324324 | contact1 |
| 1 | 674323234 | contact2 |
如果您的列数很有限,那么您可以硬编码您的查询:
select account,
contact1, contact2, contact3, contact4
from
(
select account, contact,
'contact'
+ cast(row_number() over(partition by account
order by contact) as varchar(10)) seq
from yourtable
) d
pivot
(
max(contact)
for seq in (contact1, contact2, contact3, contact4)
) piv;
请查看带演示的SQL Fiddle
如果您有未知数量的列,则必须使用动态SQL:
DECLARE @cols AS NVARCHAR(MAX),
@query AS NVARCHAR(MAX)
select @cols = STUFF((SELECT ',' + QUOTENAME(seq)
from
(
select 'contact'
+ cast(row_number() over(partition by account
order by contact) as varchar(10)) seq
from yourtable
) d
group by seq
order by seq
FOR XML PATH(''), TYPE
).value('.', 'NVARCHAR(MAX)')
,1,1,'')
set @query = 'SELECT account, ' + @cols + '
from
(
select account, contact,
''contact''
+ cast(row_number() over(partition by account
order by contact) as varchar(10)) seq
from yourtable
) x
pivot
(
max(contact)
for seq in (' + @cols + ')
) p '
execute sp_executesql @query;
请参考具有演示的SQL Fiddle。两种方法都会给您一个结果:
| ACCOUNT | CONTACT1 | CONTACT2 | CONTACT3 | CONTACT4 |
|---------|-----------|-----------|-----------|-----------|
| 1 | 324324324 | 674323234 | (null) | (null) |
| 2 | 433243443 | 833343432 | (null) | (null) |
| 3 | 787655455 | (null) | (null) | (null) |
| 4 | 455435435 | 754327545 | (null) | (null) |
| 5 | 432432432 | 432433242 | 432455553 | 543544355 |