在Python(3.5.2)中,我期望
示例代码:
repr(obj)
函数调用obj
类的魔法方法__repr __()
。然而,调用它们似乎不会产生相同的结果。有人能解释一下为什么吗?示例代码:
class parent:
def __init__(self):
self.a = "haha"
def __repr__(self):
return repr(self.a)
class child(parent):
def __init__(self):
super().__init__()
self.b="bebe"
def __repr__(self):
return "("+super().__repr__()+", "+repr(super())+", "+self.b+")"
def print1(self):
print("super().__repr__() returns:", super().__repr__())
print("repr(super()) returns:", repr(super()))
print("plom(super()).__repr__() returns:", plom(super()).__repr__())
print("repr(plom(super())) returns:", repr(plom(super())))
def plom(var):
return var
t=child()
print(t.__repr__())
print(repr(t))
print('-----')
t.print1()
print('-----')
print(plom(t).__repr__())
print(repr(plom(t)))
结果:
>>>
RESTART: test super.py
('haha', <super: <class 'child'>, <child object>>, bebe)
('haha', <super: <class 'child'>, <child object>>, bebe)
-----
super().__repr__() returns: 'haha'
repr(super()) returns: <super: <class 'child'>, <child object>>
plom(super()).__repr__() returns: 'haha'
repr(plom(super())) returns: <super: <class 'child'>, <child object>>
-----
('haha', <super: <class 'child'>, <child object>>, bebe)
('haha', <super: <class 'child'>, <child object>>, bebe)
>>>
super
返回的是一个代理对象,而不是类本身。 - juanpa.arrivillaga__repr__()
?repr
和__repr__
有何不同? - Camion