在尝试使用JMH处理超时时,我发现没有任何超时导致中断。 我可以将问题简化为以下几行:
package main.java;
import org.openjdk.jmh.Main;
import org.openjdk.jmh.annotations.*;
import org.openjdk.jmh.runner.RunnerException;
import java.io.IOException;
import java.util.concurrent.TimeUnit;
public class TimeoutBenchmark {
public static void main(String... args) throws IOException, RunnerException {
Main.main(args);
}
@Benchmark
@BenchmarkMode(Mode.AverageTime)
@Warmup(iterations = 0)
@Timeout(time = 10, timeUnit = TimeUnit.SECONDS)
public long benchmark() throws InterruptedException {
Thread.sleep(20000);
return 0;
}
}
由于Thread.sleep
处理中断,我期望每次迭代运行10秒,而不是20秒。然而,情况并非如此:
# JMH version: 1.20
# VM version: JDK 1.8.0_144, VM 25.144-b01
# VM invoker: C:\Program Files\Java\jdk1.8.0_144\jre\bin\java.exe
# VM options: -Dfile.encoding=UTF-8
# Warmup: <none>
# Measurement: 20 iterations, 1 s each
# Timeout: 10 s per iteration
# Threads: 1 thread, will synchronize iterations
# Benchmark mode: Average time, time/op
# Benchmark: main.java.TimeoutBenchmark.benchmark
# Run progress: 0,00% complete, ETA 00:03:20
# Fork: 1 of 10
Iteration 1: 20,004 s/op
Iteration 2: 20,009 s/op
Iteration 3: 20,009 s/op
Iteration 4: 20,014 s/op
Iteration 5: 20,003 s/op
Iteration 6: 20,003 s/op
Iteration 7: 20,003 s/op
为什么会这样?如何更改代码,使得每次迭代在10秒后实际中断?