我需要在C#中截取并保存/使用字符串的一部分。我认为最好的方法是使用正则表达式。我的字符串看起来像这样:
"changed from 1 to 10"
。我需要一种方法来截取这两个数字并在其他地方使用它们。有什么好的方法可以做到这一点?错误检查留作练习...
Regex regex = new Regex( @"\d+" );
MatchCollection matches = regex.Matches( "changed from 1 to 10" );
int num1 = int.Parse( matches[0].Value );
int num2 = int.Parse( matches[1].Value );
仅匹配完全相同的字符串"从x更改为y":
string pattern = @"^changed from ([0-9]+) to ([0-9]+)$";
Regex r = new Regex(pattern);
Match m = r.match(text);
if (m.Success) {
Group g = m.Groups[0];
CaptureCollection cc = g.Captures;
int from = Convert.ToInt32(cc[0]);
int to = Convert.ToInt32(cc[1]);
// Do stuff
} else {
// Error, regex did not match
}
Regex r = new Regex("*(?<FirstNumber>[0-9]{1,2})*(?<SecondNumber>[0-9]{1,2})*");
string input = "changed from 1 to 10";
string firstNumber = "";
string secondNumber = "";
MatchCollection joinMatches = regex.Matches(input);
foreach (Match m in joinMatches)
{
firstNumber= m.Groups["FirstNumber"].Value;
secondNumber= m.Groups["SecondNumber"].Value;
}
使用Expresson来帮助你,它有一个导出到C#的选项。
免责声明:正则表达式可能不正确(我的Expresso已过期:D)
这里有一段代码片段,它实现了我想要的几乎所有功能:
using System.Text.RegularExpressions;
string text = "changed from 1 to 10";
string pattern = @"\b(?<digit>\d+)\b";
Regex r = new Regex(pattern);
MatchCollection mc = r.Matches(text);
foreach (Match m in mc) {
CaptureCollection cc = m.Groups["digit"].Captures;
foreach (Capture c in cc){
Console.WriteLine((Convert.ToInt32(c.Value)));
}
}