CLGeocoder返回错误：操作无法完成。(kCLErrorDomain错误8.)

Question

一旦我得到地址字符串，我就会调用这个函数：

[[self geocoder] geocodeAddressString:addressString completionHandler:^(NSArray *placemarks, NSError *error) {
            if (error) {
                block(nil, nil, error);
            } else {
                CLPlacemark *placemark = [placemarks onlyObject];
                block(placemark, self.name, error);
            }
        }];

它会将地标返回为nil，错误返回为： Error Domain = kCLErrorDomain Code = 8“无法完成操作。（kCLErrorDomain错误8）”

我的地址字符串从此字典中检索：placeDictionary [ @“formatted_address”]：

placeDictionary = 
{
"address_components" =     (
            {
        "long_name" = "Palolem Beach";
        "short_name" = "Palolem Beach";
        types =             (
            "natural_feature",
            establishment
        );
    },
            {
        "long_name" = "South Goa";
        "short_name" = "South Goa";
        types =             (
            "administrative_area_level_2",
            political
        );
    },
            {
        "long_name" = Goa;
        "short_name" = GA;
        types =             (
            "administrative_area_level_1",
            political
        );
    },
            {
        "long_name" = India;
        "short_name" = IN;
        types =             (
            country,
            political
        );
    }
);
"adr_address" = "Palolem Beach, <span class=\"region\">Goa</span>";
"formatted_address" = "Palolem Beach, Goa";
geometry =     {
    location =         {
        lat = "15.0099648";
        lng = "74.02321859999999";
    };
    viewport =         {
        northeast =             {
            lat = "15.012671";
            lng = "74.0272093";
        };
        southwest =             {
            lat = "15.0050025";
            lng = "74.0164053";
        };
    };
};
icon = "http://maps.gstatic.com/mapfiles/place_api/icons/generic_business-71.png";
id = b286a0f7f047e162b3cab2ab3328ce95d26bdb52;
name = "Palolem Beach";
reference = "CnRwAAAAh2ZORbEpxNv5HnZlQRY_VxKLdvAd16OusSwtBlAKibDFP6roT2idnPvm-XRgMlw3iqUsZujVFrOOns76fK9we3Uddt4b3GgcWZoSqSgoYGtbHh1l5PEL_0VAwaUcswomroA3sjd3dN8lXyBSvafrrxIQONHTpwpn6IvGtYZ12pZ5ixoUENbjRTo3dCrN3aoZTM0k5EPXAjA";
types =     (
    "natural_feature",
    establishment
);
url = "https://maps.google.com/maps/place?q=Palolem+Beach&ftid=0x3bbe4551d05b02bb:0x1e1bc67d4b0fbbf5";

}

即使我使用方法：

[[self geocoder] geocodeAddressDictionary:placeDictionary completionHandler:^(NSArray *placemarks, NSError *error){

}];

它返回给我同样的错误。

- tech savvy

---

只是好奇：如果您的字典已经有地址的坐标，为什么要调用geocodeAddressString呢？ - user467105

https://dev59.com/fIjca4cB1Zd3GeqP18xh#40670608 - Deepak Thakur

CLGeocoder不太可靠，至少在印度不是。确保您调用Google API从经纬度获取地址。请参考我在上面链接中的答案。 - Deepak Thakur

Answer 1

如果提供的地址无法在苹果的地理编码器中找到，您将会看到此错误。

根据苹果文档，代码8表示kCLErrorGeocodeFoundNoResult

- Alexey Shikov

Answer 2

我认为它报错是因为geocoder找不到该地点。

请检查这段代码，我已经做了修改。

CLGeocoder *geocoder = [[CLGeocoder alloc] init];
[geocoder geocodeAddressString:@"Palolem Beach, Goa, India" completionHandler:^(NSArray* placemarks, NSError* error){
    if (!error) {

        for (CLPlacemark* aPlacemark in placemarks)
        {
            NSLog(@"place--%@", [aPlacemark locality]);
            NSLog(@"lat--%f\nlong--%f",aPlacemark.location.coordinate.latitude,aPlacemark.location.coordinate.longitude);
        }
    }
    else{

        NSLog(@"error--%@",[error localizedDescription]);
    }
}];

- Pawan Rai

Answer 3

最近发现，当使用美国邮政编码时，例如马萨诸塞州的01844，如果前面有0，则无法使用。一旦去掉了0，只使用1844，它就可以正常工作。

- J_B_UK

---

我最终向苹果报告了这个问题，现在已经修复了。你可以离开这个进程。 - J_B_UK