我希望通过JavaScript提交仅包含一个复选框的表单。但是由于未选中的复选框不会在请求中发送其键名,Symfony将无法了解表单已被提交。是否存在不太粗糙的解决方案,或者这是一种“Bug”?
表单:
表单:
class NewsletterType extends AbstractType
{
public function buildForm(FormBuilderInterface $builder, array $options)
{
$builder
->add('subscribingNewsletter', CheckboxType::class, [
'label' => 'form.label.newsletter',
'required' => false,
]);
}
public function configureOptions(OptionsResolver $resolver)
{
$resolver->setDefaults([
'data_class' => User::class,
]);
}
}
控制器的一部分:
$newsletterForm = $this->formFactory->create(NewsletterType::class, $userToEdit);
$newsletterForm->handleRequest($request);
if ($this->newsletterFormHandler->handle($newsletterForm)) {
$this->session->getFlashBag()->add('notice', 'flash_message.newsletter_changed');
return $response;
}
处理程序:
public function handle(FormInterface $form): bool
{
if (!$form->isSubmitted() || !$form->isValid()) {
return false;
}
$this->userManager->update($form->getData());
return true;
}
视图:
{{ form_start(NewsletterForm) }}
{{ form_row(NewsletterForm.subscribingNewsletter, {
attr: {class: 'js-newsletter-toggle'}
}) }}
{{ form_end(NewsletterForm) }}