我有两个JTabbedPane,JTabbedPane1和2。如何在JTabbedPane2中按下按钮以显示JTabbedPane1?
以下是JTabbedPane的代码:
public class TabbedPane extends JFrame {
public TabbedPane() {
setTitle("Tabbed Pane");
setSize(300,300);
JTabbedPane jtp = new JTabbedPane();
getContentPane().add(jtp);
JPanel1 jp1 = new JPanel1();//This will create the first tab
JPanel jp2 = new JPanel2();//This will create the second tab
//add panel .........
//example usage
public static void main (String []args){
TabbedPane tab = new TabbedPane();
}
}
这里是JPane1类:
... JLabel label1 = new JLabel();
label1.setText("This is Tab 1");
jp1.add(label1);
并在类Jpane2中添加一个名为“test”的按钮
JButton test = new JButton("Press"); jp2.add(test);
ButtonHandler phandler = new ButtonHandler();
test.addActionListener(phandler);
setVisible(true);
所以问题出现在JPanel2上的按钮的ActionListener中。
class ButtonHandler implements ActionListener{
public void actionPerformed(ActionEvent e){
// what i do now ? to call jpanel 1 show ![alt text][1]
}
}