我需要帮助,如何检查特定文件夹中时间戳超过2天的文件,然后将其删除、移动或复制到其他地方?
我需要帮助,如何检查特定文件夹中时间戳超过2天的文件,然后将其删除、移动或复制到其他地方?
一个使用 SET
命令和 ~t
修改符的简单的 FOR
循环可以返回目录中文件的最后修改日期。
请看下面的示例:
@echo off
setlocal enabledelayedexpansion
echo Files changed today %date%
FOR %%A IN (*.*) DO (
set tf=%%~tA
set fd=!tf:~0,10!
if !fd!==%date% (
echo %%F !tf!
)
)
请查看 HELP FOR
和 HELP SET
以获取详细信息。
但是,要比较超出上述简单比较的日期,您需要提取每个日期组件。
set dd=!tf:~0,2!
set mm=!tf:~3,2!
set yyyy=!tf:~6,4!
@echo off
echo System Date Time = %date% %time%
reg copy "HKCU\Control Panel\International" "HKCU\Control Panel\International-Temp" /f >nul
reg add "HKCU\Control Panel\International" /v sShortDate /d "yyyy-MM-dd" /f >nul
reg add "HKCU\Control Panel\International" /v sTimeFormat /d "HH:mm:ss" /f >nul
echo Normalized Date Time = %date% %time%
set dd=%date:~8,2%
set mm=%date:~5,2%
set yyyy=%date:~0,4%
reg copy "HKCU\Control Panel\International-Temp" "HKCU\Control Panel\International" /f >nul
最后,您需要对日期进行算术运算,您需要将DD MM YYYY格式的日期转换为天数,这也不是很明显。以下是一些代码来完成这个转换。
:days
:: Algorithm based on Fliegel-Van Flandern algorithm from the Astronomical Almanac,
:: provided by Doctor Fenton on the Math Forum (http://mathforum.org/library/drmath/view/51907.html),
:: and converted to batch code by Ron Bakowski.
SET /A Month1 = ( 1%MM% %% 100 - 14 ) / 12
SET /A Year1 = %YYYY% + 4800
SET /A days = 1461 * ( %Year1% + %Month1% ) / 4 + 367 * ( (1%MM% %% 100) - 2 -12 * %Month1% ) / 12 - ( 3 * ( ( %Year1% + %Month1% + 100 ) / 100 ) ) / 4 + (1%DD% %% 100) - 32075
SET Month1=
SET Year1=
goto :eof
奇怪的成语(1%MM% %% 100)
用于解决SET /A
解释以0开头的数字为八进制的问题。
将所有这些部分组合起来...
@echo off
setlocal enabledelayedexpansion enableextensions
reg copy "HKCU\Control Panel\International" "HKCU\Control Panel\International-Temp" /f >nul
reg add "HKCU\Control Panel\International" /v sShortDate /d "yyyy-MM-dd" /f >nul
reg add "HKCU\Control Panel\International" /v sTimeFormat /d "HH:mm:ss" /f >nul
set dd=%date:~8,2%
set mm=%date:~5,2%
set yyyy=%date:~0,4%
call :days
set /a today=!days!
FOR %%A IN (*.*) DO (
set tf=%%~tA
set fd=!tf:~0,10!
set dd=!fd:~8,2!
set mm=!fd:~5,2!
set yyyy=!fd:~0,4!
call :days
set /a age= !today!-!days!
if !age! leq 2 (
echo %%A is !age! days old
)
)
reg copy "HKCU\Control Panel\International-Temp" "HKCU\Control Panel\International" /f >nul
goto :eof
:days
:: Algorithm based on Fliegel-Van Flandern algorithm from the Astronomical Almanac,
:: provided by Doctor Fenton on the Math Forum (http://mathforum.org/library/drmath/view/51907.html),
:: and converted to batch code by Ron Bakowski.
SET /A Month1 = ( 1%MM% %% 100 - 14 ) / 12
SET /A Year1 = %YYYY% + 4800
SET /A days = 1461 * ( %Year1% + %Month1% ) / 4 + 367 * ( (1%MM% %% 100) - 2 -12 * %Month1% ) / 12 - ( 3 * ( ( %Year1% + %Month1% + 100 ) / 100 ) ) / 4 + (1%DD% %% 100) - 32075
SET Month1=
SET Year1=
goto :eof
wmic
。尝试从命令行执行以下命令:for /F "tokens=*" %G in ('wmic os get localdatetime^|find "."') do @echo =%G
。该命令以方便的 yyyymmddhhmmss...
格式返回系统本地日期和时间。 - JosefZ不确定是否要删除,但您可以使用Windows 7中的RoboCopy。参数:/MAXAGE:n将复制早于n的文件 - 我通常会将其复制到备份文件夹中,稍后在确认后从该目录中执行“全部删除”操作。
希望这可以帮助到您。