我已经设置了一个Webhook,可以将通知发布到我的服务器上的PHP页面。发送到我的服务器的通知请求如下:
POST /message/receive HTTP/1.1
Host: http://www.yoururl.com/zipwhip/api/receive
Content-Length: 581
Content-Type: application/json; charset=UTF-8
{ "body":"Thanks for texting, this is an auto reply!",
"bodySize":42,
"visible":true,
"hasAttachment":false,
"dateRead":null,
"bcc":null,
"finalDestination":"4257772300",
"messageType":"MO",
"deleted":false,
"statusCode":4,
"id":634151298329219072, "scheduledDate":null, "fingerprint":"132131532", "messageTransport":9, "contactId":3382213402, "address":"ptn:/4257772222",
"read" "dateCreated":"2015-08-19T16:53:45-07:00", "dateDeleted":null,
"dateDelivered":null,
"cc":null,
"finalSource":"4257772222",
} "dev
我尝试使用以下方法将JSON数据转换为可处理的字符串,但迄今为止什么都没有:
$inputJSON = file_get_contents('php://input');
$input= json_decode( $inputJSON, TRUE );
根据我所读的,这应该可以实现 - 我测试了以下内容,确实有效:
$webhookContent = "";
$webhook = fopen('php://input' , 'rb');
while (!feof($webhook)) {
$webhookContent .= fread($webhook, 4096);
}
fclose($webhook);
我在努力理解为什么使用file_get_contents('php://input')时无法正常工作,而我读到的所有内容都表明这是我应该使用的函数,以及为什么使用fopen('php://input', 'rb')却可以正常工作?
如果我执行var_dump($inputJSON),我会得到:
string(527) "{ "body":"Thanks for texting, this is an auto reply!",
"bodySize":42,
"visible":true,
"hasAttachment":false,
"dateRead":null,
"bcc":null,
"finalDestination":"4257772300",
"messageType":"MO",
"deleted":false,
"statusCode":4,
"id":634151298329219072, "scheduledDate":null, "fingerprint":"132131532", "messageTransport":9, "contactId":3382213402, "address":"ptn:/4257772222",
"read" "dateCreated":"2015-08-19T16:53:45-07:00", "dateDeleted":null,
"dateDelivered":null,
"cc":null,
"finalSource":"4257772222",
}"
var_dump($input)返回NULL
var_dump($inputJSON)
输出了什么? - jeroen