如何在JavaScript中将JSON数组添加到每个JSON对象？

Question

我有以下JSON对象：

{
  "status": "CREATED",
  "overrides": {
    "name": "test_override"
  },
  "package_name": "test",
  "name": "app1",
  "defaults": {
    "job": {
      "example": {
        "executors_num": "2",
        "freq_in_mins": "180",
        "executors_mem": "256M",
        "job_name": "batch_example"
      }
    }
  }
}

我想将上述JSON对象转换成类似下面这样的格式。基本上是为每个嵌套对象添加一个数组。

{
  "children": [
    {
      "status": "CREATED"
    },
    {
      "obj": "overrides",
      "children": [
        {
          "name": "test_override"
        }
        ]
        },
        {
          "package_name": "test"
        },
        {
          "name": "app1"
        },
        {
          "obj": "defaults",
          "children": [
          {
           "obj": "job",
           "children": [
           {
            "obj": "example",
            "children": [
            {
              "executors_num": "2",
              "freq_in_mins": "180",
              "executors_mem": "256M",
              "job_name": "batch_example"
            }]
          }]
        }]
      }
    ]
}

以下是我所拥有的代码：

function traverse(o, d) {
  for (i in o) {
    if (typeof(o[i])=="object") {
      console.log(i, o[i]);
      // considering only 'default' obj for now
      if(i === 'defaults') {
        d.children.push( {obj: i, "children" :[ o[i] ]});
      }
      traverse(o[i], d);
    }
  }
  return d;
}   

我最终得到了这个结果：

{"children":[{"obj":"defaults",
"children":[{"job":{"example":
{"executors_num":"2","freq_in_mins":"180","executors_mem":"256M","job_name":"batch_example"}}}]}]}

但是我似乎遇到了困难，不确定如何将children数组添加到每个嵌套对象中。有什么建议吗？

- Pavan

---

有什么确切的问题吗？有任何错误信息吗？ - Toni Leigh

请使用您评论中的代码更新您的示例。 - trenthaynes

@whipdancer 更新了示例代码。 - Pavan

你怎么称呼 traverse？ - TaoPR

@TaoP.R.var destJson = { children: [] }; var s = traverse(originalJson, destJson); - Pavan

Answer 1

the code below is a recursive function that check if the object key is an object and if so its call it self

var data = {
  "status": "CREATED",
  "overrides": {
    "name": "test_override"
  },
  "package_name": "test",
  "name": "app1",
  "defaults": {
    "job": {
      "example": {
        "executors_num": "2",
        "freq_in_mins": "180",
        "executors_mem": "256M",
        "job_name": "batch_example"
      }
    }
  }
}

function toArray(obj){
  var res = {children:[]}
   Object.keys(obj).forEach(function(key){
     var childObj = {};
     
      if(typeof obj[key] === 'object'){
        childObj[key] = toArray(obj[key])
      }
      else{
        childObj[key] = obj[key]  
      }
     res.children.push(childObj)
   })
   return res;
}

document.write(JSON.stringify(toArray(data)))

- Zamboney

---

不完全是我要找的答案..它会将一个单独的元素添加为JSON对象..相反，它应该成为父数组的子元素。 - Pavan

Answer 2

另一个提案是为每个属性在children数组中添加自己的对象。

function organize(object, result, key) {
    if (typeof object === 'object') {
        result.obj = key;
        result.children = [];
        Object.keys(object).forEach(function (k) {
            var o = {};
            result.children.push(o);
            organize(object[k], o, k);
        });
    } else {
        result[key] = object;
    }
}

var object = { "status": "CREATED", "overrides": { "name": "test_override" }, "package_name": "test", "name": "app1", "defaults": { "job": { "example": { "executors_num": "2", "freq_in_mins": "180", "executors_mem": "256M", "job_name": "batch_example" } } } },
    newObject = {};

organize(object, newObject)
document.write('<pre>' + JSON.stringify(newObject, 0, 4) + '</pre>');

- Nina Scholz