这里是测试图片：
http://images.plurk.com/tn_4134189_bf54fe8e270ce41240d534b5133884ee.gif我尝试了互联网上找到的几种方法，但都没有可行解决方案。
我正在使用以下代码片段：
Url imageUrl = new Url("http://images.plurk.com/tn_4134189_bf54fe8e270ce41240d534b5133884ee.gif");
Bitmap image = BitmapFactory.decodeStream(imageUrl.openStream());
DEBUG/skia(1441): --- decoder->decode returned false
需要帮助吗？ 谢谢。
编辑：
这些无法被解码的图像也无法在WebView中显示。但是如果在浏览器中打开，则可以查看。
我遇到了同样的问题，这个类部分地解决了我的问题：
static class FlushedInputStream extends FilterInputStream {
public FlushedInputStream(InputStream inputStream) {
super(inputStream);
}
@Override
public long skip(long n) throws IOException {
long totalBytesSkipped = 0L;
while (totalBytesSkipped < n) {
long bytesSkipped = in.skip(n - totalBytesSkipped);
if (bytesSkipped == 0L) {
int byte = read();
if (byte < 0) {
break; // we reached EOF
} else {
bytesSkipped = 1; // we read one byte
}
}
totalBytesSkipped += bytesSkipped;
}
return totalBytesSkipped;
}
}
并且:
InputStream in = null;
try {
in = new java.net.URL(imageUrl).openStream();
} catch (MalformedURLException e) {
e.printStackTrace();
} catch (IOException e) {
e.printStackTrace();
}
Bitmap image = BitmapFactory.decodeStream(new FlushedInputStream(in));
它在大多数情况下有所帮助，但这不是普遍解决方案。更多信息请参考此错误报告。
祝好运！
尝试使用以下临时解决方法：
首先添加以下类：
public static class PlurkInputStream extends FilterInputStream {
protected PlurkInputStream(InputStream in) {
super(in);
}
@Override
public int read(byte[] buffer, int offset, int count)
throws IOException {
int ret = super.read(buffer, offset, count);
for ( int i = 2; i < buffer.length; i++ ) {
if ( buffer[i - 2] == 0x2c && buffer[i - 1] == 0x05
&& buffer[i] == 0 ) {
buffer[i - 1] = 0;
}
}
return ret;
}
}
接下来，您需要使用PlurkInputStream来包装原始数据流：
Bitmap bitmap = BitmapFactory.decodeStream(new PlurkInputStream(originalInputStream));
请告诉我这是否有帮助。
编辑：
对不起，请尝试使用以下版本：
for ( int i = 6; i < buffer.length - 4; i++ ) {
if ( buffer[i] == 0x2c ) {
if ( buffer[i + 2] == 0 && buffer[i + 1] > 0
&& buffer[i + 1] <= 48 ) {
buffer[i + 1] = 0;
}
if ( buffer[i + 4] == 0 && buffer[i + 3] > 0
&& buffer[i + 3] <= 48 ) {
buffer[i + 3] = 0;
}
}
}
我尝试了所有的解决方案，但都没有解决我的问题。经过一些测试，当网络连接不稳定时，skia解码器失败的问题经常发生。对我来说，强制重新下载图像可以解决这个问题。
当图像大小较大时，问题也更加明显。
使用循环将需要我最多尝试2次，然后图像将被正确下载。
Bitmap bmp = null;
int retries = 0;
while(bmp == null){
if (retries == 2){
break;
}
bmp = GetBmpFromURL(String imageURL);
Log.d(TAG,"Retry...");
retries++;
}
试试这个：
HttpGet httpRequest = new HttpGet(url);
HttpClient httpclient = new DefaultHttpClient();
HttpResponse response = (HttpResponse) httpclient.execute(httpRequest);
HttpEntity entity = response.getEntity();
BufferedHttpEntity bufferedHttpEntity = new BufferedHttpEntity(entity);
InputStream is = bufferedHttpEntity.getContent();
Drawable d = Drawable.createFromStream(is, "");
//or bitmap
//Bitmap b = BitmapFactory.decodeStream(is);
这应该可以工作：
URL url = new URL(src);
HttpURLConnection connection = (HttpURLConnection) url.openConnection();
connection.setDoInput(true);
connection.connect();
InputStream input = connection.getInputStream();
Bitmap myBitmap = BitmapFactory.decodeStream(input);
connection.disconnect();
input.close();
myBitmap 包含了你的图片。
出于内存原因，您必须像这样实现BitmapFactory选项：
BitmapFactory.Options options = new BitmapFactory.Options();
options.inSampleSize = 4; // might try 8 also
Bitmap downloadBitmap(String url) {
final HttpClient client = AndroidHttpClient.newInstance("Android");
final HttpGet getRequest = new HttpGet(url);
try {
HttpResponse response = client.execute(getRequest);
final int statusCode = response.getStatusLine().getStatusCode();
if (statusCode != HttpStatus.SC_OK) {
if(DEBUG)Log.w("ImageDownloader", "Error " + statusCode +
" while retrieving bitmap from " + url);
return null;
}
final HttpEntity entity = response.getEntity();
if (entity != null) {
InputStream inputStream = null;
try {
inputStream = entity.getContent();
BitmapFactory.Options options = new BitmapFactory.Options();
options.inSampleSize = 4; // might try 8 also
return BitmapFactory.decodeStream(new FlushedInputStream(inputStream),null,options);
} finally {
if (inputStream != null) {
inputStream.close();
}
entity.consumeContent();
}
}
} catch (IOException e) {
getRequest.abort();
if(DEBUG)Log.w(TAG, "I/O error while retrieving bitmap from " + url, e);
} catch (IllegalStateException e) {
getRequest.abort();
if(DEBUG)Log.w(TAG, "Incorrect URL: " + url);
} catch (Exception e) {
getRequest.abort();
if(DEBUG)Log.w(TAG, "Error while retrieving bitmap from " + url, e);
} finally {
if ((client instanceof AndroidHttpClient)) {
((AndroidHttpClient) client).close();
}
}
return null;
}
也许你需要像这样实现AsyncTask： http://android-developers.blogspot.com/2010/07/multithreading-for-performance.html
这是由于Android中InputStream类中的一个错误导致的。 您可以在此处找到有效的解决方法和错误描述 http://code.google.com/p/android/issues/detail?id=6066
