使用Python 2.7.9,我正在尝试将DOS风格的目录列表拆分为单独的行,使用内置的splitlines函数。该列表是目录的一个示例,我的三引号字符串中的一行包含一个尾随反斜杠。问题在于以反斜杠结尾的行没有被拆分。
问题在于传递
# DOS-style listing of the directory "B:\"
listing = """Directory of B:\
12/15/2014 02:12 PM 1814814 BIRD.LOG
01/01/2000 12:04 AM <DIR> CONFIG
12/15/2014 02:55 PM 35060 ALLIGATOR.LOG
03/15/2013 02:06 PM <DIR> MONKEY
03/15/2013 02:06 PM <DIR> FROG
03/15/2013 02:06 PM <DIR> BADGER
2 File(s) 1849874 bytes
4 Dir(s) 1674739712 bytes free
"""
# BIRD.LOG is combined with prior line ending in a backslash
print "keepends = False"
for line in listing.splitlines(False): print repr(line)
# Setting keepends=True does not help
print "keepends = True"
for line in listing.splitlines(True): print repr(line)
这里是输出:
keepends = False
'Directory of B: 12/15/2014 02:12 PM 1814814 BIRD.LOG'
' 01/01/2000 12:04 AM <DIR> CONFIG'
' 12/15/2014 02:55 PM 35060 ALLIGATOR.LOG'
' 03/15/2013 02:06 PM <DIR> MONKEY'
' 03/15/2013 02:06 PM <DIR> FROG'
' 03/15/2013 02:06 PM <DIR> BADGER'
' 2 File(s) 1849874 bytes'
' 4 Dir(s) 1674739712 bytes free'
keepends = True
'Directory of B: 12/15/2014 02:12 PM 1814814 BIRD.LOG\n'
' 01/01/2000 12:04 AM <DIR> CONFIG\n'
' 12/15/2014 02:55 PM 35060 ALLIGATOR.LOG\n'
' 03/15/2013 02:06 PM <DIR> MONKEY\n'
' 03/15/2013 02:06 PM <DIR> FROG\n'
' 03/15/2013 02:06 PM <DIR> BADGER\n'
' 2 File(s) 1849874 bytes\n'
' 4 Dir(s) 1674739712 bytes free\n'
问题在于传递
keepends = True
参数没有变化。Python splitlines documentation没有提到任何反斜杠的特殊处理,universal newlines approach的分割行文档也是如此。我的代码示例来自单元测试,但在真实世界中,清单将通过编程方式检索。我可以想到涉及操作输入列表或其他方法的解决方法,但我想知道为什么需要解决方法。这是一个错误吗?任何建议都将不胜感激!