我正在尝试在googlemaps视口中心发生更改时，使用邮政编码向我的数据库提交查询。我知道可以使用类似以下内容的反向地理编码来完成此操作：
google.maps.event.addListener(map, 'center_changed', function(){
newCenter();
});
...
function newCenter(){
var newc = map.getCenter();
geocoder.geocode({'latLng': newc}, function(results, status){
if (status == google.maps.GeocoderStatus.OK) {
var newzip = results[0].address_components['postal_code'];
}
});
};
当然，这段代码实际上是不起作用的。所以我想知道我需要如何更改它才能从结果数组中提取邮政编码。
var zip = $.results[0].address_components[?(@.types=="postal_code")].long_name;
Romaine M. - 谢谢！如果你只需要在 Google 的第一个返回结果中找到邮政编码，你可以只做两次循环：
for(var j=0;j < results[0].address_components.length; j++){
for(var k=0; k < results[0].address_components[j].types.length; k++){
if(results[0].address_components[j].types[k] == "postal_code"){
zipcode = results[0].address_components[j].long_name;
}
}
}
places.getDetails( request_details, function(results_details, status){
// Check if the Service is OK
if (status == google.maps.places.PlacesServiceStatus.OK) {
places_postal = results_details.address_components
places_phone = results_details.formatted_phone_number
places_phone_int = results_details.international_phone_number
places_format_address = results_details.formatted_address
places_google_url = results_details.url
places_website = results_details.website
places_rating = results_details.rating
for (var i = 0; i < places_postal.length; i++ ) {
if (places_postal[i].types == "postal_code"){
console.log(places_postal[i].long_name)
}
}
}
});
这对我来说似乎非常有效，这是使用新的Google Maps API V3。如果这能帮助到任何人，请留下评论，我正在编写我的脚本...所以它可能会改变。
$zip = $data["results"][3]["address_components"];
$zip = $index[0]["short_name"];
return $http.get('//maps.googleapis.com/maps/api/geocode/json', {
params: {
address: val,
sensor: false
}
}).then(function (response) {
var model= response.data.results.map(function (item) {
// return item.address_components[0].short_name;
var short_name;
var st= $.each(item.address_components, function (value, key) {
if (key.types[0] == "postal_code") {
short_name= key.short_name;
}
});
return short_name;
});
return model;
});
使用Jquery
var postalObject = $.grep(results[0].address_components, function(n, i) {
if (n.types[0] == "postal_code") {
return n;
} else {
return null;
}
});
$scope.query.Pincode = postalObject[0].long_name;
var place = response.Placemark[0];
var point = new GLatLng(place.Point.coordinates[1], place.Point.coordinates[0]);
myAddress = place.AddressDetails.Country.AdministrativeArea.SubAdministrativeArea.Locality.Thoroughfare.ThoroughfareName
myCity = place.AddressDetails.Country.AdministrativeArea.SubAdministrativeArea.Locality.LocalityName
myState = place.AddressDetails.Country.AdministrativeArea.AdministrativeAreaName
myZipCode = place.AddressDetails.Country.AdministrativeArea.SubAdministrativeArea.Locality.PostalCode.PostalCodeNumber
一定有更优雅的方法来检索单个address_components，而不必像你刚才那样进行循环操作。
现在似乎更好的方法是从restful API获取，只需尝试：
https://maps.googleapis.com/maps/api/geocode/json?latlng=40.714224,-73.961452&key=YOUR_KEY_HERE
使用 AJAX GET 调用非常完美！
类似这样：
var your_api_key = "***";
var f_center_lat = 40.714224;
var f_center_lon = -73.961452;
$.ajax({ url: "https://maps.googleapis.com/maps/api/geocode/json?latlng="+f_center_lat+","+f_center_lon+"&key="+your_api_key,
method: "GET"
})
.done(function( res ) { if (debug) console.log("Ajax result:"); console.log(res);
var zipCode = null;
var addressComponent = res.results[0].address_components;
for (var x = 0 ; x < addressComponent.length; x++) {
var chk = addressComponent[x];
if (chk.types[0] == 'postal_code') {
zipCode = chk.long_name;
}
}
if (zipCode) {
//alert(zipCode);
$(current_map_form + " #postalcode").val(zipCode);
}
else {
//alert('No result found!!');
if (debug) console.log("Zip/postal code not found for this map location.")
}
})
.fail(function( jqXHR, textStatus ) {
console.log( "Request failed (get postal code via geocoder rest api). Msg: " + textStatus );
});
//autocomplete is the text box where u will get the suggestions for an address.
autocomplete.addListener('place_changed', function () {
//Place will get the selected place geocode and returns with the address
//and marker information.
var place = autocomplete.getPlace();
//To select just the zip code of complete address from marker, below loop //will help to find. Instead of y.long_name you can also use y.short_name.
var zipCode = null;
for (var x = 0 ; x < place.address_components.length; x++) {
var y = place.address_components[x];
if (y.types[0] == 'postal_code') {
zipCode = y.long_name;
}
}
});
我认为这是最准确的解决方案：
zipCode: result.address_components.find(item => item.types[0] === 'postal_code').long_name;
types数组中具有“postal_code”的元素，该元素可能位于最后、最前或任何位置。此外，哪个元素？您可能希望从results[0].address_components或results本身获取邮政编码：尝试两者并查看在您关心的区域中哪个更好用。一般来说，如果您关心具有完整地址的地点，则建议使用results[0].address_components，如果您关心严格包含您的latlng的邮政编码，则使用results。 - miguev