虽然回答有些晚了,但我遇到了同样的问题,这个问题帮助我解决了它们。
总结一下,我认为我应该发布我的结果,希望能加速其他人的实施。
首先是ExpandoJsonResult,你可以在你的操作中返回一个实例。或者你可以在你的控制器中覆盖Json方法并在那里返回它。
public class ExpandoJsonResult : JsonResult
{
public override void ExecuteResult(ControllerContext context)
{
HttpResponseBase response = context.HttpContext.Response;
response.ContentType = !string.IsNullOrEmpty(ContentType) ? ContentType : "application/json";
response.ContentEncoding = ContentEncoding ?? response.ContentEncoding;
if (Data != null)
{
JavaScriptSerializer serializer = new JavaScriptSerializer();
serializer.RegisterConverters(new JavaScriptConverter[] { new ExpandoConverter() });
response.Write(serializer.Serialize(Data));
}
}
}
然后是转换器(支持序列化和反序列化。请参见下面的示例以了解如何进行反序列化)。
public class ExpandoConverter : JavaScriptConverter
{
public override object Deserialize(IDictionary<string, object> dictionary, Type type, JavaScriptSerializer serializer)
{ return DictionaryToExpando(dictionary); }
public override IDictionary<string, object> Serialize(object obj, JavaScriptSerializer serializer)
{ return ((ExpandoObject)obj).ToDictionary(x => x.Key, x => x.Value); }
public override IEnumerable<Type> SupportedTypes
{ get { return new ReadOnlyCollection<Type>(new Type[] { typeof(System.Dynamic.ExpandoObject) }); } }
private ExpandoObject DictionaryToExpando(IDictionary<string, object> source)
{
var expandoObject = new ExpandoObject();
var expandoDictionary = (IDictionary<string, object>)expandoObject;
foreach (var kvp in source)
{
if (kvp.Value is IDictionary<string, object>) expandoDictionary.Add(kvp.Key, DictionaryToExpando((IDictionary<string, object>)kvp.Value));
else if (kvp.Value is ICollection)
{
var valueList = new List<object>();
foreach (var value in (ICollection)kvp.Value)
{
if (value is IDictionary<string, object>) valueList.Add(DictionaryToExpando((IDictionary<string, object>)value));
else valueList.Add(value);
}
expandoDictionary.Add(kvp.Key, valueList);
}
else expandoDictionary.Add(kvp.Key, kvp.Value);
}
return expandoObject;
}
}
您可以在ExpandoJsonResult类中看到如何使用它进行序列化。要进行反序列化,请以相同的方式创建序列化器并注册转换器,但使用其他方法。
dynamic _data = serializer.Deserialize<ExpandoObject>("Your JSON string")
非常感谢所有在这里帮助我的参与者。