使用API时从MSBUILD跳过/排除项目类型

Question

我正在使用MSBUILD API通过服务构建解决方案。

例如

var pc = new ProjectCollection();
var buildProperties = new Dictionary<string, string>
{
   {"Configuration", "Release"},
   {"Platform", "Any CPU"},
   {"OutputPath", _outputPath}
};

var buildParameters = new BuildParameters(pc);

var buildRequest = new BuildRequestData(_buildFile, buildProperties, null, new[] { "Clean", "Rebuild" }, null);            

var buildResult = BuildManager.DefaultBuildManager.Build(buildParameters, buildRequest);

我希望能够传入一个被排除的项目类型或扩展名列表。首先，我想要排除以下项目：

• 数据库项目
• WinRT 项目
• 没有项目类型 GUID 的通用 MSBUILD 文件。

通过向 MSBUILD 管理器传递一些参数，是否有任何解决此问题的方法？

- Doug

Answer 1

这可能不完全是你想要的，但我在以前的工作中恰好在使用msbuild API，并且认为这段代码可能会有用：

var basePath = "path-to-where-source-is";
var outputDir = "path-to-output";

// Setup some properties that'll apply to all projs
var pc = Microsoft.Build.Evaluation.ProjectCollection.GlobalProjectCollection;
pc.SetGlobalProperty("Configuration", "Debug");
pc.SetGlobalProperty("Platform", "Any CPU");
pc.SetGlobalProperty("OutDir", outputDir);

// Generate the metaproject that represents a given solution file
var slnProjText = SolutionWrapperProject.Generate(
    Path.Combine(basePath, "NAME-OF-SOLUTION-FILE.sln"), 
    "4.0", 
    null);

// It's now a nice (well, ugly) XML blob, so read it in
using(var srdr = new StringReader(slnProjText))
using(var xrdr = XmlReader.Create(srdr))
{
    // Load the meta-project into the project collection        
    var slnProj = pc.LoadProject(xrdr, "4.0");

    // Slice and dice the projects in solution with LINQ to
    // get a nice subset to work with
    var solutionProjects = 
        from buildLevel in Enumerable.Range(0, 10)
        let buildLevelType = "BuildLevel" + buildLevel
        let buildLevelItems = slnProj.GetItems(buildLevelType)
        from buildLevelItem in buildLevelItems
        let include = buildLevelItem.EvaluatedInclude
        where !include.Contains("Some thing I don't want to build")
        select new 
        { 
            Include=include, 
            Project = pc.LoadProject(Path.Combine(basePath, include))
        };

    // For each of them, build em!
    foreach (var projectPair in solutionProjects)
    {
        var project = projectPair.Project;
        var include = projectPair.Include;
        var outputPath = outputDir;
        project.SetProperty("OutputPath", outputPath);
        Console.WriteLine("Building project:" + project.DirectoryPath);
        var buildOk = project.Build("Build");
        if(buildOk)
        {
            Console.WriteLine("Project build success!");
        } 
        else
        {
            throw new Exception("Build failed");
        }
    }
}

- JerKimball

---

是的先生 - 解决方案包装器处理从解决方案语法（这是一个充满遗留问题的混乱）到msbuild项目语法的转换，后者更好（并且是正确的xml）。 - JerKimball