有没有办法在 Ruby 数组中查找下一个元素?
代码:
# Find ALL languages
if !debug
lang = Language.all
else
lang = Language.where("id = ? OR id = ?", 22, 32)
end
# Get all elements
elements = Element.where("human_readable IS NOT NULL")
lang.each do |l|
code = l.code.downcase
if File.exists?(file_path + code + ".yml")
File.delete(file_path + code + ".yml")
end
t1 = Time.now
info = {}
elements.each do |el|
unless l.id == 1
et = el.element_translations.where("language_id = ? AND complete = ?", l.id, true)
else
et = el.element_translations.where("language_id = ?", 1)
end
et.each do |tran|
info[code] ||= {}
info[code][el.human_readable] = tran.content.gsub("\n", "").force_encoding("UTF-8").encode!
end
end
File.open(file_path + code + ".yml", "w", :encoding => "UTF-8") do |f|
if f.write(info.to_yaml)
t2 = Time.now
puts code + ".yml File written"
puts "It took " + time_diff_milli(t1, t2).to_s + " seconds to complete"
# This is where I want to display the next item in the lang array
puts lang.shift(1).inspect
puts "*"*50
end
end
end
puts lang.shift(1).inspect
,在迭代 lang 的块内使用可能会导致一些问题。但也有可能不会。 - Mike Tunnicliffex = array[i]
和y = array[i+1]
。这甚至不是编程101,而是编程幼儿园,因此我们无法想象这就是你要问的问题。这并不是要冒犯,而是为了澄清。 - Mike Bethany