SharpSVN读取所有文件名

Question

仍然对SharpSVN有点生疏，我想要一些简单的代码来打开一个SVN仓库，并读取（至少）特定文件夹中所有文件的完整路径。

假设这个文件夹是\trunk\source。

我不想checkout或提交，只是读入一个列表。

我还想要读取所有文件，而不仅仅是更改过的文件。

- KevinDeus

Answer 1

好的，看起来我找到了一种方法...

        bool gotList;
        List<string> files = new List<string>();

        using (SvnClient client = new SvnClient())
        {
            Collection<SvnListEventArgs> list;

            gotList = client.GetList(projectPath, out list);

            if (gotList)
            {
                foreach (SvnListEventArgs item in list)
                {
                    files.Add(item.Path);
                }
            }
        }

- KevinDeus

Answer 2

我匆忙地在记事本中写下了这篇文章，抱歉。

SvnClient client = new SvnClient();
client.Authentication.DefaultCredentials = new NetworkCredential("svnuser", "svnpass");
SvnUriTarget folderTarget = new SvnUriTarget("https://mysvnserver.com/mysvnpath");
List<String> filesFound = getFolderFiles(client, folderTarget);

// GetFolderFiles
//   Function that, given a SvnClient and Target to a folder, returns a list of files
private List<String> getFolderFiles(SvnClient client, SvnTarget folderTarget)
{
    List<String> filesFound = new List<String>();
    List<SvnListEventArgs> listResults;

    if (client.GetList(folderTarget, out listResults))
    {
        foreach (SvnListEventArgs item in listResults)
            if (item.Entry.NodeKind == SvnNodeKind.File)
                filesFound.Add(item.Path);

        return filesFound;
    }
    else
       throw new Exception("Failed to retrieve files via SharpSvn");
}

- Cyrus Amiri