您可以导入Foundation和AppKit模块,然后创建NSApplication子类。但是,如果您的pyobjc代码不是代码的入口点,那么可能这不是您所寻找的。您能否更具体地说明您正在尝试使用pyobjc做什么?
以下是使用pyobjc制作简单状态栏应用程序的快速示例,无需使用xcode:
import objc
from Foundation import *
from AppKit import *
from PyObjCTools import AppHelper
class MyApp(NSApplication):
def finishLaunching(self):
statusbar = NSStatusBar.systemStatusBar()
self.statusitem = statusbar.statusItemWithLength_(NSVariableStatusItemLength)
self.icon = NSImage.alloc().initByReferencingFile_('icon.png')
self.icon.setScalesWhenResized_(True)
self.icon.setSize_((20, 20))
self.statusitem.setImage_(self.icon)
self.menubarMenu = NSMenu.alloc().init()
self.menuItem = NSMenuItem.alloc().initWithTitle_action_keyEquivalent_('Click Me', 'clicked:', '')
self.menubarMenu.addItem_(self.menuItem)
self.quit = NSMenuItem.alloc().initWithTitle_action_keyEquivalent_('Quit', 'terminate:', '')
self.menubarMenu.addItem_(self.quit)
self.statusitem.setMenu_(self.menubarMenu)
self.statusitem.setToolTip_('My App')
def clicked_(self, notification):
NSLog('clicked!')
if __name__ == "__main__":
app = MyApp.sharedApplication()
AppHelper.runEventLoop()
您可以使用py2app使其可分发:
from distutils.core import setup
import py2app
NAME = 'myapp'
SCRIPT = 'myapp.py'
VERSION = '0.1'
ID = 'myapp'
plist = dict(
CFBundleName = NAME,
CFBundleShortVersionString = ' '.join([NAME, VERSION]),
CFBundleGetInfoString = NAME,
CFBundleExecutable = NAME,
CFBundleIdentifier = 'com.yourdn.%s' % ID,
LSUIElement = '1',
)
app_data = dict(script=SCRIPT, plist=plist)
setup(
app = [app_data],
options = {
'py2app':{
'resources':[
],
'excludes':[
]
}
}
)