我正在尝试在C#中手动构建一个SOAP信封。我最初尝试通过StringBuilder逐步构建,然后通过LoadXml方法将其添加到XmlDocument中。但是,在执行时,我遇到了以下异常:
System.Xml.XmlException:名称中不能包含“:”字符,十六进制值为0x3A。第1行,第200个位置。
我要创建的信封是:
<soap:Envelope
xmlns:soap="http://schemas.xmlsoap.org/soap/envelope/"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns:xsd="http://www.w3.org/2001/XmlSchema">
<soap:Header>
<wsrp:path
soap:actor="http://schemas.xmlsoap.org/soap/actor/next"
soap:mustUnderstand="1"
xmlns:wsrp="http://schemas.xmlsoap.org/rp">
<wsrp:action>
http://abcd.com/Webservices
</wsrp:action>
<wsrp:to>
http://abcd.com/Webservices.asmx
</wsrp:to>
<wsrp:id>
uuid:aaaaa0a7-9e46-432b-8f1b-35037077601f
</wsrp:id>
</wsrp:path>
<wsu:Timestamp
xmlns:wsu="http://schemas.xmlsoap.org/ws/2002/07/utility">
<wsu:Created>
2012-11-30T10:38:13z
</wsu:Created>
<wsu:Expires>
2012-11-30T11:38:13z
</wsu:Expires>
</wsu:Timestamp>
<wsse:Security soap:mustUnderstand="1" xmlns:wsse="http://schemas.xmlsoap.org/ws/2002/07/secext">
<wsse:UsernameToken
wsu:Id="SecurityToken-00c26e1a-3b3b-400f-a99a-3aa54cf8c8ff"
xmlns:wsu="http://schemas.xmlsoap.org/ws/2002/07/utility">
<wsse:Username>username</wsse:Username>
<wsse:Password Type="wsse:PasswordText">password</wsse:Password>
<wsse:Nonce>NBzqolcwIZrAOYw1vLyucDM3sQQ=</wsse:Nonce>
<wsu:Created>2012-11-30T10:38:13z</wsu:Created>
</wsse:UsernameToken>
</wsse:Security>
</soap:Header>
<soap:Body>
<MethodName xmlns="http://abcd.com/Webservices">
<ValueField>Ford</ValueField>
</MethodName>
</soap:Body>
</soap:Envelope>
我很难理解为什么编译器不喜欢“:”。有没有更好的方法来解决这个问题/我在这里做错了什么?
StringBuilder
是构建 XML 最笨拙的方式之一,建议使用XDocument
。 - Dour High Arch