合并开放时间相似的日期

Question

我该如何在PHP中（使用CodeIgniter）编写一个函数，将具有相似开放时间的商店的营业日合并在一起。例如，如果我们有：

Mon 9am-5pm
Tue 9am-5pm
Wed 9am-5pm
Thu 9am-5pm
Fri 9am-5pm
Sat 9am-7pm
Sun 9am-7pm

我希望将这段代码简化为：

Mon-Fri 9am-5pm
Sat-Sun 9am-7pm

我该如何在不使用长长的if/else或case ifs语句的情况下完成这个任务？我正在使用CodeIgniter..

- Nyxynyx

---

你把defs存储在哪里？是在一个数组中，以天为键，以小时为值吗？ - Majid Fouladpour

Answer 1

<?php
$openHours = array(
    'Mon' => '9am-5pm',
    'Tue' => '9am-5pm',
    'Wed' => '9am-9pm',
    'Thu' => '9am-5pm',
    'Fri' => '9am-5pm',
    'Sat' => '9am-7pm',
    'Sun' => '9am-7pm'
);

$summaries = array();
foreach ($openHours as $day => $hours) {
    if (count($summaries) === 0) {
        $current = false;
    } else {
        $current = &$summaries[count($summaries) - 1];
    }
    if ($current === false || $current['hours'] !== $hours) {
        $summaries[] = array('hours' => $hours, 'days' => array($day));
    } else {
        $current['days'][] = $day;
    }
}

foreach ($summaries as $summary) {
    if (count($summary['days']) === 1) {
        echo reset($summary['days']) . ' ' . $summary['hours'] . PHP_EOL;
    } else {
        echo reset($summary['days']) . '-' . end($summary['days']) . ' ' . $summary['hours'] . PHP_EOL;
    }
}

codepad示例

- peaceman

---

干得好。你可以用 $summary[$hours][] = $day; 来替换整个 if/else 语句。 - Austin

当他们决定在周三晚些时候继续营业时会发生什么？ - gilly3

嗯，实际上这会搞乱结果。 - peaceman

Answer 2

如果您想要以下格式：

Sun-Tue，Fri-Sat：11am-12am；Wed：10am-12am；Thu：9am-12am

这将分组处理一周内的不同时间和日期：

<?php
$open_hours = array (
    "Sun" => "11am-12am",
    "Mon" => "11am-12am",
    "Tue" =>  "11am-12am",
    "Wed" =>  "10am-12am",
    "Thu" =>  "9am-12am",
    "Fri" =>  "11am-12am",
    "Sat" =>  "11am-12am"
);

$result = [];
foreach ($open_hours as $day => $hours) {
    if (empty($result) || $previous !== $hours) {
        $result[$hours][] = $day;
    } elseif ($previous === $hours) {
        $key = array_key_last($result[$hours]);
        $current = strtok($result[$hours][$key], '-');
        $result[$hours][$key] = $current.'-'.$day;
    }
    $previous = $hours;
}

// build output (joining days with ,)
$output = [];
foreach ($result as $hours => $days) {
    $output[] = implode(', ', $days).': '.$hours;
}
// join with ;'s and output
echo implode('; ', $output);

https://3v4l.org/tKOlI

- Lawrence Cherone