我很久以来一直在寻找答案,但是无论我尝试什么,都会遇到不同的错误。
我有一段可用的代码:
Dim arkwyn As Variant
arkwyn = Array(1, 2, 3, "stats-obl")
For Each x In arkwyn
....
Next
但我需要在更复杂的工作表中使用类似的方法。此外,它需要快速执行,因为它将成为更复杂的更新过程的一部分,该过程不断跟踪工作表中的许多字段。
您能否请看一下并帮助我正确地完成它?
Private Function RowNo(ByVal text1 As String)
RowNo = Columns(2).Find(text1, Lookat:=xlWhole).Row
End Function
Dim t1r As Variant
Dim t1 As Integer
t1r = Array("1.2", "1.3", "1.4", "1.5", "1.6.2", "1.8", "1.9", "1.13.1.1", _
"1.13.1.2", "1.13.2")
For t1 = LBound(t1r) To UBound(t1r)
Select Case UCase(Cells(RowNo(t1), 3).Value)
Case "x"
Rows(RowNo(t1) + 1).Hidden = False
Case Else
Rows(RowNo(t1) + 1).Hidden = True
End Select
Next t1
感谢您的回答,我尝试进一步实现并创建了以下内容:
Dim ColAn As Long
ColAn = 4
Dim YtQ1Ar As Variant
Dim Y1q, rY1q As Long
YtQ1Ar = Array("1.2", "1.3", "1.4", "1.5", "1.6", "1.7", "1.7.1", "1.7.2", _
"1.7.3", "1.7.4", "1.7.5", "1.7.6", "1.7.7", "1.7.8", "1.7.9", "1.7.10", "1.7.11")
For Y1q = LBound(YtQ1Ar) To UBound(YtQ1Ar)
rY1q = RowNo(YtQ1Ar(Y1q))
Rows(rY1q).Hidden = (UCase(Cells(RowNo("1."), ColAn).Value) <> "TAK")
Next Y1q
这个想法是,单元格的值应该显示特定数量的行。但我一直得到“运行时错误91:对象变量或 With 块变量未设置”的提示。我在哪里犯了错?