我有一个字典,其中每个键都是一组值的元组。我想使用sorted()
方法按照元组的第一个元素对字典进行排序。我的代码如下:
def mapData(header_list, dict_obj):
master_dict = {}
client_section_list = []
for element in header_list:
for row in dict_obj:
if (row['PEOPLE_ID'], row['DON_DATE']) == element:
client_section_list.append(row)
element = list(element)
element_list = [client_section_list[0]['DEDUCT_AMT'],
client_section_list[0]['ND_AMT'],
client_section_list[0]['DEDUCT_YTD'],
client_section_list[0]['NONDEDUCT_YTD']
]
try:
element_list.append((float(client_section_list[0]['DEDUCT_YTD']) +
float(client_section_list[0]['NONDEDUCT_YTD'])
))
except ValueError:
pass
element.extend(element_list)
element = tuple(element)
master_dict[element] = client_section_list
client_section_list = []
return sorted(master_dict, key=lambda key: key[master_dict[(1)]]
最后一行是我试图找到一种方法来对它进行排序。我的元组看起来像这样:
(312178078,6/22/15,25,0,25,0,25.0)
sorted
函数中,您需要使用dict.items()
。return sorted(master_dict.items(), key=lambda key: key[0][0])
可以实现您想要的功能。 - cziemba