如何将CIImage转换为CMSampleBufferRef

Question

我正在使用AVCapturesession录制视频，我在didrecive sample buffer方法中以CMSamplbufferRef的形式接收输出。我已将其转换为CIImage并进行了一些更改，现在我想将该CIImage转换为CMSampleBufferRef。是否有人可以帮助我， 我浏览了很多但没有找到答案，希望能在这里找到。

- kmReddy

---

你找到解决方案了吗？它对你有用吗？https://dev59.com/MnbZa4cB1Zd3GeqPLvBe#19916522 - user924

Answer 1

我并不是原作者，感谢Crop CMSampleBufferRef的作者。

CVPixelBufferRef pixelBuffer;
CVPixelBufferCreate(kCFAllocatorSystemDefault, 640, 480, kCVPixelFormatType_32BGRA, NULL, &pixelBuffer);

CVPixelBufferLockBaseAddress( pixelBuffer, 0 );

CIContext * ciContext = [CIContext contextWithOptions: nil];
[ciContext render:ciImage toCVPixelBuffer:pixelBuffer];
CVPixelBufferUnlockBaseAddress( pixelBuffer, 0 );

CMSampleTimingInfo sampleTime = {
    .duration = CMSampleBufferGetDuration(sampleBuffer),
    .presentationTimeStamp = CMSampleBufferGetPresentationTimeStamp(sampleBuffer),
    .decodeTimeStamp = CMSampleBufferGetDecodeTimeStamp(sampleBuffer)
};

CMVideoFormatDescriptionRef videoInfo = NULL;
CMVideoFormatDescriptionCreateForImageBuffer(kCFAllocatorDefault, pixelBuffer, &videoInfo);

CMSampleBufferRef oBuf;
CMSampleBufferCreateForImageBuffer(kCFAllocatorDefault, pixelBuffer, true, NULL, NULL, videoInfo, &sampleTime, &oBuf);

- Jack

---

停止使用ciContext render以避免占用过多的CPU资源。 - famfamfam