使用 jq 合并 JSON 对象

Question

我有以下的 JSON 结构

{

    "a": "aVal",
    "x": {
      "x1": "x1Val",
      "x2": "x2Val"
    }
    "y": {
      "y1": "y1Val"
    }
}

我想要将 "x3": "x3Val","x4": "x4Val" 添加到 x 中。因此输出应该是：

{
    ...
    "x": {
      ....
      "x3": "x3Val",
      "x4": "x4Val",
    }
    ...
}

是否可以使用jq？

- theapache64

Answer 1

当然，对于 jq 来说，这相当简单。

jq '.x += {"x3": "x3Val","x4": "x4Val"}' file.json

输出：

{
  "a": "aVal",
  "x": {
    "x1": "x1Val",
    "x2": "x2Val",
    "x3": "x3Val",
    "x4": "x4Val"
  },
  "y": {
    "y1": "y1Val"
  }
}

- RomanPerekhrest

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简单而完美 (y) - theapache64

Answer 2

是的，只要您在第8行结束括号}后添加逗号（否则 jq 将无法解析您的输入JSON数据）：

$ jq '.x.x3="x3val"|.x.x4="x4val"' file
{
  "a": "aVal",
  "x": {
    "x1": "x1Val",
    "x2": "x2Val",
    "x3": "x3val",
    "x4": "x4val"
  },
  "y": {
    "y1": "y1Val"
  }
}

或者，如果您需要将值作为参数传递，请使用选项--arg：

jq --arg v3 "x3val" --arg v4 "x4val" '.x.x3=$v3|.x.x4=$v4' file

- oliv

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感谢您的回复。 - theapache64