public class Main {
static int a = 0;
public static void main(String[] args) {
try {
test();
System.out.println("---");
test2();
}
catch(Exception e) {
System.out.println(a + ": outer catch");
a++;
}
}
public static void test()
{
try {
throw new Exception();
}
catch (Exception e) {
System.out.println(a + ": inner catch");
a++;
}
finally {
System.out.println(a + ": finally");
a++;
}
}
public static void test2() throws Exception
{
try {
throw new Exception();
}
finally {
System.out.println(a + ": finally");
a++;
}
}
}
输出结果为:
0: inner catch
1: finally
---
2: finally
3: outer catch
为什么在test()
中,catch会在finally之前发生,而在test2()
中则相反?
catch
块会怎样? - Snackoverflow