自定义的Zedgraph ToolStripMenuItem在被点击时不会被选中

Question

我通过以下方式自定义了右键菜单：

lineGraphControl1.ContextMenuBuilder += new ZedGraphControl.ContextMenuBuilderEventHandler(MyContextMenuBuilder);

并且

private void MyContextMenuBuilder(ZedGraphControl control, ContextMenuStrip menuStrip, Point mousePt, ZedGraphControl.ContextMenuObjectState objState)
{
    // create a new menu item
    ToolStripMenuItem item = new ToolStripMenuItem();
    // This is the user-defined Tag so you can find this menu item later if necessary
    item.Name = "simple_cursor";
    // This is the text that will show up in the menu
    item.Text = "Simple Cursor";
    item.CheckOnClick = true;
    // Add a handler that will respond when that menu item is selected
    item.Click += new System.EventHandler(DisplaySimpleCursor);
    // Add the menu item to the menu
    menuStrip.Items.Add(item);
}

但是菜单简单光标在被点击时不会被选中。我尝试在函数DisplaySimpleCursor()中强制发送器，但它不起作用。

当我调试我的应用程序时，我看到在DisplaySimpleCursor()中，发送器的属性Checked被设置为true。

我错过了什么？

- Thomas Ayoub

Answer 1

试试这个。

 private bool check;
    public bool Check
    {
        get { return check; }
        set { check= value; }
    }
private void MyContextMenuBuilder(ZedGraphControl control, ContextMenuStrip menuStrip, Point mousePt, ZedGraphControl.ContextMenuObjectState objState)
{
    ToolStripMenuItem item = new ToolStripMenuItem();
    item.Name = "simple_cursor";
    item.Text = "Simple Cursor";
    item.CheckOnClick = true;
        item.Checked = Check; //add this
    item.Click += new System.EventHandler(DisplaySimpleCursor);
    menuStrip.Items.Add(item);
}


 private void DisplaySimpleCursor(object sender, EventArgs e)
        {
            Check = false==Check;
        }

- Rasim Cekic

Answer 2

由于菜单是基于热加载构建的，因此每次菜单隐藏时，checkOnClick 属性都无效，因为对象被销毁了（我猜测）。

解决方案是设置属性：

// showOneCursor is a bool describing my need and toggled on click
item.Checked = showOneCursor; 

- Thomas Ayoub