有依赖关系
[tupelo "0.1.68"]
我们可以编写以下代码。我留下了许多
spy
表达式,以便...
(ns clj.core
(:use tupelo.core)
(:require [clojure.core :as clj]
[schema.core :as s]
[tupelo.types :as tt]
[tupelo.schema :as ts]
))
(s/set-fn-validation! true)
(def data [ {:a 1 :b 2} {:a 3 :b 4} {:a 1 :b 6} {:a 3 :b 9} {:a 5 :b 1} {:a 6 :b 1} ] )
(defn accum-smallest-b-entries
[cum-map-a2b
new-a-b-map
]
(newline)
(println "---------------------------------")
(let [new-a-map (select-keys new-a-b-map [:a] )
_ (spyx new-a-map)
new-b-map (select-keys new-a-b-map [:b] )
_ (spyx new-b-map)
curr-b-map (get cum-map-a2b new-a-map)
_ (spyx curr-b-map)
next-b-map (if (or (nil? curr-b-map)
(< (grab :b new-b-map) (grab :b curr-b-map)))
new-b-map
curr-b-map)
_ (spyx next-b-map)
]
(spyx (assoc cum-map-a2b new-a-map next-b-map))))
(def a2b-map (reduce accum-smallest-b-entries {} data))
(spyx a2b-map)
(defn combine-keyvals-from-a2b-map
[cum-result
a2b-entry
]
(newline)
(println "combine-keyvals-from-a2b-map")
(println "---------------------------------")
(spyx cum-result)
(spyx a2b-entry)
(let [combined-ab-map (glue (first a2b-entry) (second a2b-entry))
_ (spyx combined-ab-map)
new-result (append cum-result combined-ab-map)
_ (spyx new-result)
]
new-result))
(def a-and-b-map (reduce combine-keyvals-from-a2b-map [] a2b-map))
(spyx a-and-b-map)
(defn -main [] )
运行代码我们得到:
---------------------------------
new-a-map => {:a 1}
new-b-map => {:b 2}
curr-b-map => nil
next-b-map => {:b 2}
(assoc cum-map-a2b new-a-map next-b-map) => {{:a 1} {:b 2}}
---------------------------------
new-a-map => {:a 3}
new-b-map => {:b 4}
curr-b-map => nil
next-b-map => {:b 4}
(assoc cum-map-a2b new-a-map next-b-map) => {{:a 1} {:b 2}, {:a 3} {:b 4}}
---------------------------------
new-a-map => {:a 1}
new-b-map => {:b 6}
curr-b-map => {:b 2}
next-b-map => {:b 2}
(assoc cum-map-a2b new-a-map next-b-map) => {{:a 1} {:b 2}, {:a 3} {:b 4}}
---------------------------------
new-a-map => {:a 3}
new-b-map => {:b 9}
curr-b-map => {:b 4}
next-b-map => {:b 4}
(assoc cum-map-a2b new-a-map next-b-map) => {{:a 1} {:b 2}, {:a 3} {:b 4}}
---------------------------------
new-a-map => {:a 5}
new-b-map => {:b 1}
curr-b-map => nil
next-b-map => {:b 1}
(assoc cum-map-a2b new-a-map next-b-map) => {{:a 1} {:b 2}, {:a 3} {:b 4}, {:a 5} {:b 1}}
---------------------------------
new-a-map => {:a 6}
new-b-map => {:b 1}
curr-b-map => nil
next-b-map => {:b 1}
(assoc cum-map-a2b new-a-map next-b-map) => {{:a 1} {:b 2}, {:a 3} {:b 4}, {:a 5} {:b 1}, {:a 6} {:b 1}}
a2b-map => {{:a 1} {:b 2}, {:a 3} {:b 4}, {:a 5} {:b 1}, {:a 6} {:b 1}}
combine-keyvals-from-a2b-map
---------------------------------
cum-result => []
a2b-entry => [{:a 1} {:b 2}]
combined-ab-map => {:a 1, :b 2}
new-result => [{:a 1, :b 2}]
combine-keyvals-from-a2b-map
---------------------------------
cum-result => [{:a 1, :b 2}]
a2b-entry => [{:a 3} {:b 4}]
combined-ab-map => {:a 3, :b 4}
new-result => [{:a 1, :b 2} {:a 3, :b 4}]
combine-keyvals-from-a2b-map
---------------------------------
cum-result => [{:a 1, :b 2} {:a 3, :b 4}]
a2b-entry => [{:a 5} {:b 1}]
combined-ab-map => {:a 5, :b 1}
new-result => [{:a 1, :b 2} {:a 3, :b 4} {:a 5, :b 1}]
combine-keyvals-from-a2b-map
---------------------------------
cum-result => [{:a 1, :b 2} {:a 3, :b 4} {:a 5, :b 1}]
a2b-entry => [{:a 6} {:b 1}]
combined-ab-map => {:a 6, :b 1}
new-result => [{:a 1, :b 2} {:a 3, :b 4} {:a 5, :b 1} {:a 6, :b 1}]
a-and-b-map => [{:a 1, :b 2} {:a 3, :b 4} {:a 5, :b 1} {:a 6, :b 1}]
回想起来,如果我们能保证每个输入映射都像 {:a :b} 这样简单,那么它可以更加简化,因为我们可以将其简化为一系列 2D 点,例如 [n m],因为关键字 :a 和 :b 将是冗余的。
(apply min-key :b (filter #(= (:a %) 3) list))
,它通过过滤掉所有:a
= 3 的值来在列表中找到:b
的最小值,但我需要手动输入:a
的值。 - Campbell Wray