我需要将一个嵌套的XML反序列化为对象。由于我对Linq to XML不熟悉,因此在此分享了一些代码以便您更好地了解我想从XML中获取什么。
以下是我的XML:
这里是酒店类。
以下是我的XML:
<ba:BA_Test xmlns:ba="http://www.testing.com" TimeStamp="2015-04-16T18:15:41.974+0100">
<ba:Hotels>
<ba:Hotel HotelCode="3258_811" HotelName="BEST WESTERN">
<ba:RoomTypes>
<ba:RoomType RoomTypeCode="22_3258_811" RoomTypeName="Double plus 1 adult OR 2 childr"/>
<ba:RoomType RoomTypeCode="17_3258_811" RoomTypeName="Double plus 1 adult or child"/>
<ba:RoomType RoomTypeCode="1_3258_811" RoomTypeName="Room for 1"/>
<ba:RoomType RoomTypeCode="18_3258_811" RoomTypeName="Room for 1 Adult and 1 Child"/>
<ba:RoomType RoomTypeCode="2_3258_811" RoomTypeName="Room for 2"/>
</ba:RoomTypes>
<ba:AvailabilityGroup AvailabilityGroupCode="14254_3258_811" AvailabilityGroupName="Standard">
<ba:RoomRates>
<ba:RoomRate RoomRateCode="49069_3258_811" RoomTypeCode="1_3258_811" RoomRateName="Standard Room"/>
<ba:RoomRate RoomRateCode="49071_3258_811" RoomTypeCode="2_3258_811" RoomRateName="Standard Room"/>
<ba:RoomRate RoomRateCode="49462_3258_811" RoomTypeCode="2_3258_811" RoomRateName="Vienna Highlights - Standard Room - For 2 People"/>
<ba:RoomRate RoomRateCode="58367_3258_811" RoomTypeCode="1_3258_811" RoomRateName="Standard Room - Tigrafriends"/>
<ba:RoomRate RoomRateCode="58369_3258_811" RoomTypeCode="2_3258_811" RoomRateName="Standard Room - Tigrafriends"/>
<ba:RoomRate RoomRateCode="70518_3258_811" RoomTypeCode="2_3258_811" RoomRateName="Advent days (shopping) in Vienna - Standard Room"/>
</ba:RoomRates>
</ba:AvailabilityGroup>
</ba:Hotel>
</ba:Hotels>
</ba:BA_Test>
这是我的 Linq to XML 代码,但它没有嵌套。
XDocument xdoc = XDocument.Load(@"D:\response.xml");
XNamespace nsr = "http://www.test.com";
// using Linq To Xml parse and load Objects
List<Hotel> hotel = (from res in xdoc.Root.Descendants(nsr + "Hotel")
select new Hotel
{
hotel_code = res.Attribute("HotelCode").Value,
hotel_name = res.Attribute("HotelName").Value,
}).ToList<Hotel>();
这里是酒店类。
///
[System.CodeDom.Compiler.GeneratedCodeAttribute("System.Xml", "4.0.20329.23234")]
[System.SerializableAttribute()]
[System.Diagnostics.DebuggerStepThroughAttribute()]
[System.ComponentModel.DesignerCategoryAttribute("code")]
[System.Xml.Serialization.XmlTypeAttribute(AnonymousType = true, Namespace = "http://www.testing.com")]
[System.Xml.Serialization.XmlRootAttribute(Namespace = "http://www.testing.com", IsNullable = false)]
public partial class Hotel
{
private room_types room_typesField;
private List<availability_group> availability_groupField;
private string hotel_codeField;
private string hotel_nameField;
///
public room_types room_types
{
get
{
return this.room_typesField;
}
set
{
this.room_typesField = value;
}
}
///
public List<availability_group> availability_group
{
get
{
return this.availability_groupField;
}
set
{
this.availability_groupField = value;
}
}
我该如何将这个XML转换为单个的LINQ查询呢?任何帮助都将不胜感激。提前致谢。