我正在使用boost program_options 1.50.0。
我想让我的程序foobar允许以下内容: foobar --debug 2 --debug 3
在boost program_options的代码中,有一个名为regex.cpp的示例,展示了如何创建新类型并为该类型创建验证器。
我尝试过它,并且它起作用了,但现在我不能使用其他add_options() typed_value选项,例如default_value、composing等。
这是我到目前为止尝试的:
#include <boost/program_options.hpp>
using namespace boost;
using namespace boost::program_options;
#include <iostream>
using namespace std;
struct lastmultioccurrenceint {
public:
lastmultioccurrenceint(int n) : n(n) {}
int n;
};
void validate(boost::any& v,
const std::vector< std::string >& xs,
//const std::vector< std::basic_string<charT> >& xs,
lastmultioccurrenceint* , int)
{
using namespace boost::program_options;
cerr << "IN VALIDATE" << endl;
//validators::check_first_occurrence(v);
string s = validators::get_single_string(xs);
if (!v.empty()) {
cerr << "\tPRINTTING MULTIOCCURENCE WARNING, allowing v to be overwritten" << endl;
cerr << "\tEarlier value was: " << boost::any_cast<int>(v) << endl;
cerr << "\tNew value is: " << s << endl;
}
try {
//v = any(lastmultioccurrenceint(lexical_cast<int>(sx)));
//v = any(lexical_cast<int>(sx)); // works
v = any(lexical_cast<int>(s));
//v = any(lexical_cast<lastmultioccurrenceint>(s));
//v = any(4);
//}
/*catch(const bad_lexical_cast&) {
boost::throw_exception(validation_error::invalid_option_value(s));
} */
}
catch(const bad_lexical_cast&) {
throw validation_error(validation_error::invalid_option_value);
}
cerr << "made it through" << endl;
int main (int argc, char **argv) {
variables_map m_varMap;
// define style
// unix_style = (allow_short | short_allow_adjacent | short_allow_next
// | allow_long | long_allow_adjacent | long_allow_next
// | allow_sticky | allow_guessing
// | allow_dash_for_short),
// ... allows typical unix-style options
// allow_long_disguise = can use "-" instead of "--"
// Reference: http://www.boost.org/doc/libs/1_42_0/doc/html/boost/program_options/command_line_style/style_t.html
//
try {
ProgOpts::command_line_style::style_t style = ProgOpts::command_line_style::style_t(
ProgOpts::command_line_style::unix_style |
//ProgOpts::command_line_style::case_insensitive |
ProgOpts::command_line_style::allow_long_disguise );
options_description options("YDD");
//lastmultioccurrenceint debugOpt;
options.add_options()
("debug", value<lastmultioccurrenceint>(), "debug value (0-4), default is 0 (performance mode)")
//("debug", value<lastmultioccurrenceint>(&debugOpt)->default_value(0)->composing(), "debug value (0-4), default is 0 (performance mode)")
;
//ProgOpts::parsed_options firstPreParsed = ProgOpts::command_line_parser(argc,argv).options(options).style(style).allow_unregistered().run();
ProgOpts::parsed_options firstPreParsed = ProgOpts::command_line_parser(argc,argv).options(options).allow_unregistered().run();
ProgOpts::store(firstPreParsed, m_varMap);
ProgOpts::notify(m_varMap);
}
/*catch (boost::program_options::multiple_occurrences &e) {
cerr << "GOT MULTIPLES" << endl;
cerr << "Option Name: " << e.get_option_name() << endl;
cerr << e.what() << endl;
}
catch(boost::bad_any_cast& e) {
cerr << "WRONG TYPE" << endl;
cerr << e.what() << endl;
} */
catch(std::exception& e) {
cerr << "SOMETHING ELSE" << endl;
cerr << e.what() << endl;
}
catch(...) {
cerr << "UNKNOWN ERROR" << endl;
}
cerr << "DEBUG OPT IS: " << m_varMap["debug"].as<int>() << endl;
}
如果我执行以下命令: foobar --debug 2 --debug 3
如果我注释掉当前的调试选项....
("debug", value<lastmultioccurrenceint>(), "debug value (0-4), default is 0 (performance mode)")
...并取消以下两行的注释:
lastmultioccurrenceint debugOpt;
("debug", value<lastmultioccurrenceint>(&debugOpt)->default_value(0)->composing(), "debug value (0-4), default is 0 (performance mode)")
如果这样做,甚至无法编译。
你知道怎样做可以让我同时使用default_value和composing吗?可能需要从typed_value继承,但我还没有找到一个好的方法。
foobar --debug 2 --debug 3
,使用std::vector<int>
作为选项类型。 - Sam Miller