使用Python、geopy和shapely实现GPS定位

Question

使用Python、geopy和shapely实现GPS定位

3

我正在尝试处理以下情况：

Getting polygon coordinates from google earth

Getting boundaries with Shapely:

>>> polygon = Polygon([(53.349459,-6.260159),(53.349366,-6.260126),(53.349383,-6.260012),(53.349478,-6.260053),(53.349459,-6.260159)])   
>>> polygon.bounds
(53.349366, -6.260159, 53.349478, -6.260012)

I am getting 2 coordinates, which are 2 border points on the top of my figure.

Getting distance with geopy

And now I am stuck... trying to figure out:
1. How to find 2 other border points (in the bottom)
2. How to detect whether a user is near (e.g. 3 meters) the polygon from any side? (left, right, up, down). in this case, I need to know not only the edges border points, but also all the border points from left, right, up and down? I can calculate the distance between the user location and the polygon, but what point to from polygon to take dynamically? Can I use existing libs for this, like geopy and Shapely?

- user1790755

这可能更适合在http://gis.stackexchange.com上提问。 - RickyA

Bounds返回您的多边形的边界框。它是多边形适合其中的最小矩形。如果您查看它，它不是顶点坐标。 - RickyA

1个回答

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- RickyA · Accepted Answer

如果我理解正确，您有一堆Shapely多边形，并且想要测试任意点是否靠近这些形状。对于这个问题，Shapely提供了distance：

from shapely.geometry import Point, Polygon
polygon = Polygon([(53.349459,-6.260159),
                   (53.349366,-6.260126),
                   (53.349383,-6.260012),
                   (53.349478,-6.260053),
                   (53.349459,-6.260159)])
testpoint = Point(53.349459,-6.260190)
dist = polygon.distance(testpoint)
print(dist)
>>> 3.09999999999e-05

请注意：距离是以弧度而不是米为单位，因此您需要进行转换。