我无法通过ID找到现有的实体,具体原因未知。
该实体具有以下视图:
@Entity
@Table(name = "persons")
@NamedEntityGraph(name = "includeRemunerationAndCredential",attributeNodes = {
@NamedAttributeNode("remunerations"),
@NamedAttributeNode("credentials")
})
@JsonSerialize
public class Person implements Serializable {
@Id
@GeneratedValue(strategy = GenerationType.AUTO)
private Long id;
@Column(name = "first_name", nullable = false, length = 50)
@NotNull
private String firstName;
@Column(name= "second_name", nullable = false, length = 50)
@NotNull
private String secondName;
@Column(name = "father_name", length = 50)
private String fatherName;
@Column(name = "phone_number", length = 20)
private String phoneNumber;
@Column(name = "date_of_birth")
private LocalDateTime dateOfBirth;
@Column(name = "role", nullable = false, length = 50)
@Enumerated(EnumType.STRING)
private Role role;
@Column(name = "date_of_creation", nullable = false)
@NotNull
private LocalDateTime dateOfCreation;
@ManyToOne(fetch = FetchType.EAGER)
@JoinColumn(name = "carwash")
private CarWash carWash;
@OneToMany(fetch = FetchType.LAZY, mappedBy = "person")
private List<Remuneration> remunerations;
@OneToMany(fetch = FetchType.LAZY, mappedBy = "person")
private Set<Credential> credentials;
@Column(name = "enable", nullable = false)
private Boolean enable;
@ManyToOne(fetch = FetchType.EAGER)
@JoinColumn(name = "owner", nullable = false)
private Owner owner;
// getters and setters
@Override
public boolean equals(Object o) {
if (this == o) return true;
if (o == null || getClass() != o.getClass()) return false;
Person person = (Person) o;
return id != null ? id.equals(person.id) : person.id == null;
}
@Override
public int hashCode() {
return id != null ? id.hashCode() : 0;
}
@Override
public String toString() {
return "Person{" +
"id=" + id +
", firstName='" + firstName + '\'' +
", secondName='" + secondName + '\'' +
", fatherName='" + fatherName + '\'' +
", phoneNumber='" + phoneNumber + '\'' +
", dateOfBirth=" + dateOfBirth +
", role=" + role +
", dateOfCreation=" + dateOfCreation +
", carWash=" + (carWash == null ? carWash : carWash.getId()) +
", remunerations=" + (remunerations == null ? remunerations : remunerations.size()) +
", enable=" + enable +
", owner=" + (owner == null ? "N/A" : owner.getName()) +
'}';
}
我的DAO有以下视图:
public interface PersonDAO extends CrudRepository<Person, Long> {}
我的服务由这个类提供。
@Service("userDetailsService")
@Transactional
public class MyUserDetailService implements UserDetailsService {
@Autowired
PersonDAO personDAO;
@Override
@Transactional(readOnly = true)
public UserDetails loadUserByUsername(String name) throws UsernameNotFoundException {
//final Iterable<Person> all = personDAO.findAll();
final Person one = personDAO.findOne(15L);
return null;
}
如果在服务中注释掉personDAO.findAll()
,那么personDAO.findOne(15L)
将返回null,但是如果取消对findAll()
的注释,则可以找到findOne(15L)
。如何修复这个问题,使得findOne
能够在不执行findAll()
的情况下工作?