如何在单例方法中实现AVAudioPlayer？

Question

如何在单例方法中实现AVAudioPlayer？

3

这是我的代码：

class SomeAudioManager: NSObject
{

    class var sharedInstance: SomeAudioManager{
        struct Static {
            static var onceToken: dispatch_once_t = 0
            static var instance: SomeAudioManager? = nil
        }
        dispatch_once(&Static.onceToken) {
            Static.instance = SomeAudioManager()
        }
        return Static.instance!
    }
    func audioView(songname: NSString,format: NSString)
    {
        let audioPlayer:ava
        audioPlayer=try AVAudioPlayer(contentsOfURL: NSURL(fileURLWithPath: NSBundle.mainBundle().pathForResource(songname, ofType:format)!), fileTypeHint: AVFileTypeMPEGLayer3)
        audioPlayer!.delegate=self;
        self.audioPlayer!.play()
    }
}

AVAudioPlayer属于NSObject，但我无法实现它。

当我输入let audioPlayer: AVAudio时，它没有显示任何内容。

- Kishore Kumar

2个回答

2

就评论中提到的单例部分而言，您可能应该使用类似于以下内容的代码：

class MyAudioPlayer: NSObject, AVAudioPlayerDelegate {
    private static let sharedPlayer: MyAudioPlayer = {
        return MyAudioPlayer()
    }()

    private var container = [String : AVAudioPlayer]()

    static func playFile(name: String, type: String) {
        var player: AVAudioPlayer?
        let key = name+type
        for (file, thePlayer) in sharedPlayer.container {
            if file == key {
                player = thePlayer
                break
            }
        }
        if player == nil, let resource = NSBundle.mainBundle().pathForResource(name, ofType:type) {
            do {
                player = try AVAudioPlayer(contentsOfURL: NSURL(fileURLWithPath: resource), fileTypeHint: AVFileTypeMPEGLayer3)
            } catch {
                // error
            }
        }
        if let thePlayer = player {
            if thePlayer.playing {
                // already playing
            } else {
                thePlayer.delegate = sharedPlayer
                sharedPlayer.container[key] = thePlayer
                thePlayer.play()
            }
        }
    }
}

使用方法如下：

MyAudioPlayer.playFile("Breach", type: "mp3")

- Matic Oblak

非常感谢 @Matic Oblak，提前祝您圣诞节快乐 :) - Kishore Kumar

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- Matic Oblak · Accepted Answer

虽然这没有太多意义，但是对我来说可以编译：

import AVFoundation
class SomeAudioManager: NSObject, AVAudioPlayerDelegate
{
    class var sharedInstance: SomeAudioManager {
        struct Static {
            static var onceToken: dispatch_once_t = 0
            static var instance: SomeAudioManager? = nil
        }
        dispatch_once(&Static.onceToken) {
            Static.instance = SomeAudioManager()
        }
        return Static.instance!
    }
    func audioView(songname: String,format: String) {
        let audioPlayer: AVAudioPlayer

        do {
            audioPlayer = try AVAudioPlayer(contentsOfURL: NSURL(fileURLWithPath: NSBundle.mainBundle().pathForResource(songname, ofType:format)!), fileTypeHint: AVFileTypeMPEGLayer3)
            audioPlayer.delegate = self;
            audioPlayer.play()
        } catch {
            // error
        }
    }
}

所以你需要导入框架，在Swift中，try-catch语法是do-try-catch。一些其他的语法错误也被修复了。

顺便说一下，在Swift中单例不是这样使用的。

用法：

class someOtherClass {
    func doSomething() {
        SomeAudioManager().audioView("name_here", format: "format_here")
        SomeAudioManager.sharedInstance.audioView("name_here", format: "format_here")
    }
}