将zip文件解压到内存中？

Question

如何将zip文件解压到内存中？

我的尝试（在.getvalue()上返回None）：

from zipfile import ZipFile
from StringIO import StringIO

def extract_zip(input_zip):
    return StringIO(ZipFile(input_zip).extractall())

- user1438003

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请参见：https://dev59.com/Vm025IYBdhLWcg3w76lq - J0ANMM

Answer 1

extractall 方法是将文件提取到文件系统中，所以你不会得到你想要的结果。要在内存中提取文件，请使用 ZipFile.read() 方法。

如果你确实需要将整个内容保存在内存中，可以这样做：

def extract_zip(input_zip):
    input_zip=ZipFile(input_zip)
    return {name: input_zip.read(name) for name in input_zip.namelist()}

- mata

Answer 2

如果你经常使用内存归档，我建议你制作一个工具。类似这样：

# Works in Python 2 and 3.

try:
    import BytesIO
except ImportError:
    from io import BytesIO  # Python 3
import zipfile


class InMemoryZip(object):
    def __init__(self):
        # Create the in-memory file-like object for working w/IMZ
        self.in_memory_zip = BytesIO()

    # Just zip it, zip it
    def append(self, filename_in_zip, file_contents):
        # Appends a file with name filename_in_zip and contents of
        # file_contents to the in-memory zip.
        # Get a handle to the in-memory zip in append mode
        zf = zipfile.ZipFile(self.in_memory_zip, "a", zipfile.ZIP_DEFLATED, False)

        # Write the file to the in-memory zip
        zf.writestr(filename_in_zip, file_contents)

        # Mark the files as having been created on Windows so that
        # Unix permissions are not inferred as 0000
        for zfile in zf.filelist:
            zfile.create_system = 0

        return self

    def read(self):
        # Returns a string with the contents of the in-memory zip.
        self.in_memory_zip.seek(0)
        return self.in_memory_zip.read()

    # Zip it, zip it, zip it
    def writetofile(self, filename):
        # Writes the in-memory zip to a physical file.
        with open(filename, "wb") as file:
            file.write(self.read())


if __name__ == "__main__":
    # Run a test
    imz = InMemoryZip()
    imz.append("testfile.txt", "Make a test").append("testfile2.txt", "And another one")
    imz.writetofile("testfile.zip")
    print("testfile.zip created")

- Deviacium

Answer 3

可能的原因：

1.该模块目前无法处理多磁盘ZIP文件。 (或)
2.请检查StringIO.getvalue()是否出现了Unicode错误。

- dilip kumbham

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不，extractall 不会返回任何东西（默认情况下是 None），这就是他得到的结果。 - mata