我有一个函数:
def func(something):
for j in tqdm(something):
...
被以下方法调用:
joblib.Parallel(n_jobs=4)((joblib.delayed)(s) for s in something_else)
现在,这创建了4个重叠的tqdm进度条。是否可能获得4个独立更新的进度条?
我有一个函数:
def func(something):
for j in tqdm(something):
...
被以下方法调用:
joblib.Parallel(n_jobs=4)((joblib.delayed)(s) for s in something_else)