如何动态检查一个字符串是否包含多个子字符串匹配？

Question

我正在尝试构建一个搜索建议，返回最佳匹配项。以下是我的代码和注释：

    /*
    string = {"Canna Terra PLUS 50 Litres", "Canna Vega Tent", "Canna Bio Vega", "Super Canna 50 max" }
    search = "Canna Vega"  this can be dynamic ranging up to 4 words search term

    The expected return array would be

    {"Canna Vega Tent", "Canna Bio Vega" }

    */

    function loadSuggest(string,search){

        if( search.length < 3 ){ 
            return; // suggest is loaded only if the search term is more than 3 letter
        }

        var terms = search.split(' '); // split the search term with spaces
        var i;

        for(i = 0; i < string.length; i++){

            /*
            how to dynamically check and return
            the results containing more than one term match ?
            I have tried indexOf() but that fails with dynamic number of words matching
            */

        }
        return resultArray;
    }

我在代码注释中提到，我正在尝试找到一个包含搜索词中所有单词的字符串的最佳匹配。

- Clain Dsilva

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"abcdefabcfjbjabc"，你想找出其中有3个匹配项是"abc"。 - void

@void no，例如字符串“abc bbc ccf efg”，搜索项为“abc ccf”，我想知道该字符串中是否同时包含“abc”和“ccf”。 - Clain Dsilva

Answer 1

尝试一下：使用 Array.prototype.every 检查是否所有搜索词都存在，然后使用 Array.prototype.filter 进行过滤。

以下是演示：

var string = ["Canna Terra PLUS 50 Litres", "Canna Vega Tent","Canna Bio Vega", "Super Canna 50 max"];

function loadSuggest(string, search) {
  var terms = search.split(' ');
  return string.filter(function(element) {
    return terms.every(function(e) {
      return element.toLowerCase().indexOf(e.toLowerCase()) !== -1;
    });
  });
}

console.log(loadSuggest(string, "Canna vega"));

- kukkuz

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那是一个完美的答案，它非常有效，我已经接受了你的答案，非常感谢。 - Clain Dsilva