我想将我的代码从:
string path = @"c:\Directory\test.xml";
XmlSerializer s = new XmlSerializer(typeof(Car));
TextReader r = new StreamReader(path);
Car car = (Car)s.Deserialize(r);
r.Close();
我需要将XML转换为字符串,然后将字符串转换为对象Car的代码。
这个可行吗?
我想将我的代码从:
string path = @"c:\Directory\test.xml";
XmlSerializer s = new XmlSerializer(typeof(Car));
TextReader r = new StreamReader(path);
Car car = (Car)s.Deserialize(r);
r.Close();
我需要将XML转换为字符串,然后将字符串转换为对象Car的代码。
这个可行吗?
public static string XmlSerializeToString(this object objectInstance)
{
var serializer = new XmlSerializer(objectInstance.GetType());
var sb = new StringBuilder();
using (TextWriter writer = new StringWriter(sb))
{
serializer.Serialize(writer, objectInstance);
}
return sb.ToString();
}
public static T XmlDeserializeFromString<T>(this string objectData)
{
return (T)XmlDeserializeFromString(objectData, typeof(T));
}
public static object XmlDeserializeFromString(this string objectData, Type type)
{
var serializer = new XmlSerializer(type);
object result;
using (TextReader reader = new StringReader(objectData))
{
result = serializer.Deserialize(reader);
}
return result;
}
使用它:
//Make XML
var settings = new ObjectCustomerSettings();
var xmlString = settings.XmlSerializeToString();
//Make Object
var settings = xmlString.XmlDeserializeFromString<ObjectCustomerSettings>();
var xml = @"<car/>";
var serializer = new XmlSerializer(typeof(Car));
using (var reader = new StringReader(xml))
{
var car = (Car)serializer.Deserialize(reader);
}
这是一行代码,接受一个XML字符串text
和预期对象类型YourType
。与其他答案并没有太大区别,只是将其压缩成了一行:
var result = (YourType)new XmlSerializer(typeof(YourType)).Deserialize(new StringReader(text));
static T DeserializeXml<T>(string sourceXML) where T : class
{
var serializer = new XmlSerializer(typeof(T));
T result = null;
using (TextReader reader = new StringReader(sourceXML))
{
result = (T) serializer.Deserialize(reader);
}
return result;
}
以下内容是从通用XML字符串反序列化中抄袭而来:
public static T DeserializeFromXmlString<T>(string xmlString)
{
var serializer = new XmlSerializer(typeof(T));
using (TextReader reader = new StringReader(xmlString))
{
return (T) serializer.Deserialize(reader);
}
}
public static T XmlDeserializeFromString<T>(this string objectData) { return (T)XmlDeserializeFromString(objectData, typeof(T)); }
我将编辑主贴。 - OmzigStringReader
是缺失的部分。谢谢。 - primo