我想要为密码进行一些模式匹配,发现了一个关于正则表达式的示例,但是当我输入一个应该被认为是“强”的密码时,却得到了相反的结果。例如,字符串“JlcimYQF+EkHVA*”得分为1,这意味着字符串模式在正则表达式中没有被匹配,但我不确定原因。
以下是代码:
以下是代码:
public class PasswordAdvisor
{
public static PasswordScore CheckStrength(string password)
{
int score = 1;
if (password.Length < 12)
return PasswordScore.TooShort;
if (password.Length >= 16)
score++;
if (Regex.Match(password, @"/\d+/", RegexOptions.ECMAScript).Success)
score++;
if (Regex.Match(password, @"/[a-z]/", RegexOptions.ECMAScript).Success &&
Regex.Match(password, @"/[A-Z]/", RegexOptions.ECMAScript).Success)
score++;
if (Regex.Match(password, @"/.[!,@,#,$,%,^,&,*,?,_,~,-,£,(,)]/", RegexOptions.ECMAScript).Success)
score++;
return (PasswordScore)score;
}
}
声明:
var passwordStrengthScore = PasswordAdvisor.CheckStrength(@"JlcimYQF+EkH*VA");
Console.WriteLine((int)passwordStrengthScore);
switch (passwordStrengthScore)
{
case PasswordScore.TooShort:
Console.WriteLine("Password is too short");
break;
case PasswordScore.Weak:
Console.WriteLine("Password is very weak");
break;
case PasswordScore.Medium:
Console.WriteLine("OK password");
break;
case PasswordScore.Strong:
Console.WriteLine("Strong password");
break;
case PasswordScore.VeryStrong:
Console.WriteLine("Very strong password");
break;
}
/
分隔符。将@"/.[!,@,#,$,%,^,&,*,?,_,~,-,£,(,)]/"
替换为@"[!,@#$%^&*?_~£()-]"
以要求其中一个特殊字符。在除Regex.Match(password, @"\d+", RegexOptions.ECMAScript)
语句之外的所有语句中,可以安全地移除RegexOptions.ECMAScript
选项。 - Wiktor Stribiżew