MySQL获取行号

4
我有这样一个表格:
+------+----------+------------+
|   id |  1_value |   2_value  |
+------+----------+------------+
|    3 |   foo1   |   other    |
|   10 |   fooX   |   stuff    |
|   13 |   fooJ   |   here     |
|   22 |   foo7   |   and      |
|   31 |   foou   |   here     |
+------+----------+------------+

我希望能够得到行号。

我尝试过类似这样的做法:

SELECT  id, @curRow := @curRow + 1 AS row_number
FROM    table
JOIN    (SELECT @curRow := 0) r

而且它确实起作用...

+------+--------------+
|   id |  row_number  | 
+------+--------------+
|    3 |   1          | 
|   10 |   2          |
|   13 |   3          |
|   22 |   4          |
|   31 |   5          |
+------+--------------+

但是如果我尝试选择特定的行呢?

SELECT  id, @curRow := @curRow + 1 AS row_number
FROM    srwk_esp_registration
JOIN    (SELECT @curRow := 0) r
WHERE ID = 22

在这种情况下,行号是1,但它应该是4。
我该怎么做才能实现这个目标?
2个回答

6
如果您不想声明一个变量(SET @rownum something)...

通常,我的查询是:

SELECT t.* FROM ticket t

t.* 前或后添加 @i:=@i+1 as row_number,并将表连接到 (SELECT @i:=0)

SELECT @i:=@i+1 as row_number, t.* FROM ticket t, (SELECT @i:=0) AS temp

尝试修改示例查询,希望能有所帮助。

祝你好运!


5

使用子查询试试:

SELECT * 
FROM (
    SELECT id,
        @curRow := @curRow + 1 AS row_number
    FROM srwk_esp_registration
    JOIN (
        SELECT @curRow := 0
        ) r
    ) sub
WHERE sub.ID = 22

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