Laravel：如何向函数传递参数？

Question

我正在尝试在Laravel的whereHas函数中传递两个参数，因为否则它将无法使用$businessid，但是它会抛出一个错误，请问有谁可以帮忙吗？

错误信息：

FatalThrowableError in HomeController.php line 16: Type error: Too few arguments to function App\Http\Controllers\Business\User\HomeController::App\Http\Controllers\Business\User{closure}(), 1 passed in C:\web\vendor\laravel\framework\src\Illuminate\Database\Eloquent\Builder.php on line 938 and exactly 2 expected

代码：

<?php

namespace App\Http\Controllers\Business\User;

use App\User;
use App\Http\Controllers\Controller;
use Illuminate\Http\Request;
use Auth;
use App\Database\Frontend\Roleplay\Business\Businesses;
use App\Database\Frontend\User\Player;

class HomeController extends Controller
{
    public function getView(Request $request, $businessid)
    {
        $workerCount = Player::whereHas("roleplay", function($q2, $businessid) {
            $q2->where('business_id', $businessid);
        })->count();

        $workersWorkingCount = Player::where('currently_working', '1')->whereHas("roleplay", function($q2, $businessid) {
            $q2->where('business_id', $businessid);
        })->count();

        $workersOnlineCount = Player::where('online', '1')->whereHas("roleplay", function($q2, $businessid) {
            $q2->where('business_id', $businessid);
        })->count();

        $workersOfflineCount = Player::where('online', '0')->whereHas("roleplay", function($q2, $businessid) {
            $q2->where('business_id', $businessid);
        })->count();

        return view('business.home', compact(
            'workerCount',
            'workersWorkingCount',
            'workersOnlineCount',
            'workersOfflineCount'));
    }
}

- Josh Hallow

Answer 1

这是如何将变量传递给函数的方法。

        $workerCount = Player::whereHas("roleplay", function($q2) use ($businessid) {
            $q2->where('business_id', $businessid);
        })->count();

- Saeed Prez