XML序列化命名空间

Question

我在我的代码中遇到了命名空间的问题。我想要的是下面的XML：

<?xml version="1.0" encoding="utf-8"?>
<ClassToSerialize Type="Customer" Name="Some Name" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://www.123.org/namespace C:\Schema\ClassToSerialize.xsd" 
xmlns:Test="http://www.Test.org/" xmlns="http://www.nrf-arts.org/namespace">
  <Address>
    <Line1>Addr1</Line1>
    <Line2>Addr2</Line2>
  </Address>
</ClassToSerialize>

What I'm getting is this XML:

<?xml version="1.0" encoding="utf-8"?>
<ClassToSerialize xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:schemaLocation="http://www.123.org/namespace C:\Schema\ClassToSerialize.xsd"
 xmlns:Test="http://www.Test.org/" xmlns:xmlns="http://www.nrf-arts.org/namespace" Type="Customer" Name="Some Name">
  <Address>
    <Line1>Addr1</Line1>
    <Line2>Addr2</Line2>
  </Address>
</ClassToSerialize>

主要区别如下：

1. xmlns:schemaLocation= needs to be xsi:schemaLocation=
2. xmlns:xmlns= needs to be xmlns=
3. Attributes Order, I would prefer the Attributes to be presented before the namespace attributes (This is not a big Issue, just nice to have)

目前我正在做的是将1和2中序列化字符串中的值替换为我想要的值，这是一个可行的 hack，但我怀疑是否有一种方法可以修改命名空间代码以在该点处执行此操作？

以下是我正在使用的代码，如何更改 GetNameSpace() 以满足我在1和2点中所需的要求？同时，我能否重新排序属性？

public partial class Form1 : Form
{
    public Form1()
    {
        InitializeComponent();
    }

    private void button1_Click(object sender, EventArgs e)
    {
        ClassToSerialize myInstance = new ClassToSerialize();
        myInstance.Type = "Customer";
        myInstance.Name = "Some Name";
        myInstance.AddressField = new Address("Addr1", "Addr2");

        String sString = SerializeObject<ClassToSerialize>(myInstance, GetNameSpace());

        //Hack to achieve what I want from namespaces
        sString = sString.Replace("xmlns:schemaLocation=", "xsi:schemaLocation=");
        sString = sString.Replace("xmlns:xmlns=", "xmlns=");
    }

    private XmlSerializerNamespaces GetNameSpace()
    {
        XmlSerializerNamespaces xsNS = new XmlSerializerNamespaces();

        xsNS.Add("xsi", "http://www.w3.org/2001/XMLSchema-instance");
        xsNS.Add("xmlns", "http://www.nrf-arts.org/namespace");
        xsNS.Add("schemaLocation", "http://www.123.org/namespace C:\\Schema\\ClassToSerialize.xsd");
        xsNS.Add("Test", "http://www.Test.org/");

        return xsNS;
    }

    public static string SerializeObject<X>(X toSerialize, XmlSerializerNamespaces xmlNameSpace)
    {
        string strRetVal = "";
        try
        {
            XmlSerializer xmlSerializer = new XmlSerializer(toSerialize.GetType());
            StringWriter textWriter = new StringWriter();

            using (StringWriter writer = new Utf8StringWriter())
            {
                xmlSerializer.Serialize(writer, toSerialize, xmlNameSpace);
                strRetVal = writer.ToString();
            }
        }
        catch (Exception ex)
        {
            string strError = ex.ToString();
        }

        return strRetVal;
    }
}

public class Utf8StringWriter : StringWriter
{
    public override Encoding Encoding
    {
        get { return Encoding.UTF8; }
    }
}

    public class ClassToSerialize
{
    [XmlAttribute()]
    public string Type { get; set; }

    [XmlAttribute()]
    public string Name { get; set; }

    [XmlElement("Address")]
    public Address AddressField { get; set; }
}

public class Address
{
    [XmlElement, DefaultValue("")]
    public string Line1 { get; set; }

    [XmlElement, DefaultValue("")]
    public string Line2 { get; set; }

    public Address()
    {

    }

    public Address(string L1, string L2)
    {
        Line1 = L1;
        Line2 = L2;
    }
}

- KF-SoftwareDev

---

schemaLocation 不是一个命名空间。 - John Saunders

Answer 1

1. 您可以添加xsi：schemaLocation，方法是添加一个合成属性，类似于如何向根c＃对象XmlSerializer添加xsi schemalocation的答案中的回答--但使用属性而不是字段。如果您使用字段，则实际上会增加内存中类的占用空间。

2. 要定义一个默认命名空间xmlns =“ http://www.nrf-arts.org/namespace”，您可以将[XmlRoot（“ClassToSerialize”，Namespace =“ http:// www.nrf-arts.org / namespace“]）应用于您的 ClassToSerialize 或分配一个 XmlRootAttribute 覆盖并将其传递给 XmlSerializer 构造函数。如果选择后者，请确保缓存序列化程序。

3. 除了实现IXmlSerializable之外（有点繁琐），我不知道是否可能使用XmlSerializer控制属性顺序。然而，XML规范规定“在开始标记或空元素标记中属性规范的顺序没有意义”，因此建议不要担心它。

因此，以下内容应该可以解决问题。请注意，我将您的GetNameSpace()移动到了ClassToSerialize内部，并将其重命名为GetAdditionalNamespaces（）：

[XmlRoot("ClassToSerialize", Namespace="http://www.nrf-arts.org/namespace")]
public class ClassToSerialize
{
    public static XmlSerializerNamespaces GetAdditionalNamespaces()
    {
        XmlSerializerNamespaces xsNS = new XmlSerializerNamespaces();

        xsNS.Add("xsi", "http://www.w3.org/2001/XMLSchema-instance");
        xsNS.Add("Test", "http://www.Test.org/");

        return xsNS;
    }

    [XmlAttribute("schemaLocation", Namespace = "http://www.w3.org/2001/XMLSchema-instance")]
    public string XSDSchemaLocation
    {
        get
        {
            return "http://www.123.org/namespace C:\\Schema\\ClassToSerialize.xsd";
        }
        set
        {
            // Do nothing - fake property.
        }
    }

    [XmlAttribute()]
    public string Type { get; set; }

    [XmlAttribute()]
    public string Name { get; set; }

    [XmlElement("Address")]
    public Address AddressField { get; set; }
}

- dbc